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Applications of Derivatives Test - 11

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Applications of Derivatives Test - 11
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  • Question 1
    1 / -0.25

     

    If f(x) =  ; g(x) = where 0

     

  • Question 2
    1 / -0.25

     

     f : R → R be a differentiable function x ∈R. If tangent drawn to the curve at any point x ∈(a, b) always lie below the curve, then

     

  • Question 3
    1 / -0.25

     

    A value of C for which the conclusion of Mean Value Theorem holds for the function f(x) = loge  x on the interval [1, 3] is

     

  • Question 4
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    The function f(x) = x(x + 3) e–x/2 satisfies all the conditions of Rolle ’s theorem in [–3, 0]. The value of c which verifies Rolle ’s theorem, is

     

    Solution

     

     

    f(x) = x (x + 3)e –x/2 is continuous in [–3, 0] 
    and f ′(x)=(x2 + 3x) (–1/2)e-x/2 + (2x + 3)e –x/2  
    = –1/2(x2 –x –6)e –x/2  
    Therefore f ′(x) exists (i.e., finite) for all x  
    Also f(–3) = 0, f (0) = 0  
    So that f(–3) = f(0) 
    Hence all the three conditions of the theorem are satisfied. 
    Now consider f ′(c)=0  
    i.e., –1/2(c2 –c –6)e –c/2 = 0  
    c2 –c –6 = 0  
    (c + 2) (c –3) = 0 c = 3 or –2  
    Hence there exists –2 ∈(–3, 0) such that  
    f ′(–2) = 0

     

     

  • Question 5
    1 / -0.25

     

     x3  – 3x2  –  9x + 20 is

     

  • Question 6
    1 / -0.25

     

     f(x) = x2  - x sin x is

     

  • Question 7
    1 / -0.25

     

    The number of values of `c 'of Lagrange 's mean value theorem for the function,

    f(x) = (x – 1) (x – 2) (x – 3), x ∈(0, 4) is

     

  • Question 8
    1 / -0.25

     

    If f(x) and g(x) are differentiable in [0, 1] such that f(0) = 2, g(0) = 0, f(1) = 6, g(1) = 2, then Rolle 's theorem is applicable for which of the following

     

  • Question 9
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    Equation 3x2  + 4ax + b = 0 has at least one root in (0, 1) if

     

  • Question 10
    1 / -0.25

     

    Function for which LMVT is applicable but Rolle 's theorem is not

     

  • Question 11
    1 / -0.25

     

     LMVT is not applicable for which of the following ?

     

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