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Logic Gates Test - 1

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Logic Gates Test - 1
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  • Question 1
    1 / -0.25
    Which one is the Universal Gate?
    Solution

    The correct answer is NOR gate.

    Concept:

    • A Universal Gate is a gate by which every other gate can be realized.
    • AND, OR, NOT, etc. are basic gates.
    • NAND, NOR  are the universal gate.

    Example:

    NOT, AND and OR gate realization using NAND gate is as shown:

  • Question 2
    1 / -0.25
    With OR operation, 1 + 1 = 
    Solution

    Concept:

    OR gate: If any of the input is high, it produces a high output.

    The Boolean algebra for OR gate is X = A + B

    Analysis:

    A = 1, B = 1

    X = 1 + 1 = 1

    AND Gate: If both the inputs are high, it produces a high output.

    The Boolean algebra for AND gate is X = A. B

    NOT gate: It inverts the input. Whatever the input is given, it changes its value at the output.

    The Boolean algebra for NOT gate is X = X̅

  • Question 3
    1 / -0.25

    The truth table given below corresponds to-

    A (input)B (input)Y (output)
    001
    010
    100
    110
    Solution

    The correct answer is option 1) i.e. NOR

    CONCEPT:

    • Truth table: A truth table is a mathematical table used to represent the output of a given function based on the combination of input variables.
      • A truth table has two columns: the first column shows the combination of input variables and the last column shows the final output for each input.
    • Logic gateLogic gates are the basic building blocks of a digital system.
      • ​A logic gate works on the principle of Boolean function which is a logical operation performed using one or more binary inputs that produce a single binary output.
      • The boolean function uses only two variables zero or one.
      • The relationship between these inputs and the output is based on a certain logic. Based on this, logic gates are given names.
      • A few logic gates along with their symbol and truth table are as follows:

    EXPLANATION:

    The given truth table matches with the NOR logic gate.

    Additional Information

    • The NOR gate is obtained by connecting the two basic logic gates - the OR gate and the NOT gate in series.
  • Question 4
    1 / -0.25

    Identify the logic operation carried out by the following circuit.

    Solution

    CONCEPT:

    • The branch of algebra which deals with the values of the variables in the form of the truth values true and false is called Boolean algebra.
    • True and false are usually denoted by 1 and 0 respectively.

    EXPLANATION:

    \(\bar C = \overline {A\;A} = \bar A\)

    \(\bar D = \overline {B\;B} = \bar B\)

    \(Y = \overline {\bar A\;\bar B} = \overline {\bar A} + \overline {\bar B} = A + B\)

    This is OR gate. So option 4 is correct.

    Boolean Laws

    Law

    Dual Pair

    Remark

    A + B = B + A

    A.B = B.A

    Commutative Law

    A + (B + C) = (A + B) + C

    A (BC) = (AB) C

    Associative Law

    A (B + C) = AB + AC

    A + (BC) = (A + B) (A + C)

    Distributive Law

    A + 1 = 1

    A.1 = A

    Identity Law/Redundancy Law

    A + 0 = A

    A.0 = 0

    A + A = A

    A.A = A

    A + A̅ = 1

    A.A̅ = 0

    A + AB = A

    A (A + B) = A

    Absorption Law

    A̅ = A

    -

    Involution Law

    A + A̅B = A + B

    A(A̅ + B) = A

    -

    B̅ + B̅ = B

    -

    -

  • Question 5
    1 / -0.25
    If the output is 1 when the AND gate is applied between A and B, then the value of A and B are:
    Solution

    CONCEPT

    Logic gates: 

    • It is an electric circuit, which works on simple Boolean algebra to perform a logical operation for one or more binary inputs that produce a single binary output.

    Types of Logic gates:

    AND Gate: If both the inputs are high, it produces a high output.

    • The Boolean algebra for AND gate is X = A. B

    OR gate: If any of the input is high, it produces a high output.

    • The Boolean algebra for OR gate is X = A + B

    NOT gate: It inverts the input. Whatever the input is given, it changes its value at the output.

    • The Boolean algebra for NOT gate is X = X̅

    EXPLANATION:

    • In AND gate the output is 1 only when both the input is 1.
    • So, If the output is 1 then,

    A = 1 and B = 1.

    • Hence, option 1 is correct.
  • Question 6
    1 / -0.25
    If A = 1 and B = 0, then in terms of Boolean algebra, A + B̅ =
    Solution

    CONCEPT:

    • The branch of algebra that deals with the values of the variables in the form of the truth values i.e., true and false are called Boolean algebra.
    • True and false are usually denoted by 1 and 0 respectively.

    EXPLANATION:

    Given that:

    A = 1

    B = 0

    ∴ B̅ = 1 (Since B̅ is reverse of B)

    A + B̅ = 1 + 1 = 1 (Since A + A = A)

    A + B̅ = 1 = A

    Boolean Laws

    Law

    Dual Pair

    Remark

    A + B = B + A

    A.B = B.A

    Commutative Law

    A + (B + C) = (A + B) + C

    A (BC) = (AB) C

    Associative Law

    A (B + C) = AB + AC

    A + (BC) = (A + B) (A + C)

    Distributive Law

    A + 1 = 1

    A.1 = A

    Identity Law/Redundancy Law

    A + 0 = A

    A.0 = 0

    A + A = A

    A.A = A

    A + A̅ = 1

    A.A̅ = 0

    A + AB = A

    A (A + B) = A

    Absorption Law

    \(\overline{\overline A} = A\)

    -

    Involution Law

    A + A̅B = A + B

    A(A̅ + B) = A

    -

    B̅ + B̅ = B

    -

    -

  • Question 7
    1 / -0.25

    Identify the logic gate?

    Solution

    CONCEPT:

    • Logic gate: The digital circuit that can be analyzed with the help of Boolean algebra is called a logic gate or logic circuit.
    • A logic gate has two or more inputs but only one output.

    EXPLANATION:

    • NAND gate: It a combination of an AND and a NOT gate.
    • It is obtained by connecting the output fo an AND gate to the input of a NOT gate.
    • It is described by the Boolean expression: \(Y = \overline {A \cdot B}\)
    • The above logic gate is the NAND gate.
    • The truth table of NAND gate:

    A

    B

    A⋅B = Y’

    Y

    0

    0

    0

    1

    0

    1

    0

    1

    1

    0

    0

    1

    1

    1

    1

    0

  • Question 8
    1 / -0.25
    The output of a NOR gate is HIGH if ______.
    Solution

    Concept:

    • universal gate is a gate which can implement any Boolean function without need to use any other gate type.
    • The NAND and NOR gates are universal gates.
    • That means we can implement any logic function using NAND and NOR gates without need of AND, OR or NOT gates.
    • NOR gate is formed by connecting a NOT gate at the output of OR gate.
    • NAND gate is formed by connecting NOT gate the output of AND gate.

     

    Truth Table of NOR gate is given:

    Input

    Output

    0 0

    1

    0 1

    0

    1 0

    0

    1 1

    0

    The output of NOR gate is high when all inputs are low.

    Explanation:

    • As we see the truth table for NOR gate :
    • When both the input is low (0), then output is high (1).
    • As one input is low (0) and another input is high (1) or vice-versa, then output is low (0).
    • When both the input is high (1), then output is low (0).

    So when the output of NOR gate is high if all inputs are low.

  • Question 9
    1 / -0.25
    When both the input signals A and B of the NOR & NAND gate are connected together, The output of the resultant circuit will be equivalent to
    Solution

    CONCEPT:

    • Logic gate: The digital circuit that can be analyzed with the help of Boolean algebra is called a logic gate or logic circuit.
    • logic gate has two or more inputs but only one output.
    • Logic gates works on the ruth table.

    EXPLANATION:

    • When both the input signals A and B of NOR & NAND gate are connected together, we have one common input connection hence the resultant output will be NOT gated.
    • As shown when both the inputs are combined in either NAND or NOR gate, they both will behave like a NOT gate

    This will be the truth table for both NAND and NOR logic gate when their inputs are connected.

    Input

    Output

    0

    1

    1

    0

  • Question 10
    1 / -0.25

    The correct Boolean operation represented by the circuit diagram drawn is 

    Solution

    From the given circuit we can see that,

    • Two Keys are connected parallel to a LED and a resistor.
    • Hence if any of the keys is open, no current will flow through keys and hence bulb will glow
    • But if both the keys are closed current will start flowing from keys instead of LEDs, since current (I) will always flow where resistance is minimum.
    • Which means the truth table for the given circuit can be given as
    • Here 1 shows key is closed and current can flows through it
    • And 0 shows key is open and current can’t flow through it

     

    A

    B

    Y

    Boolean representation

    0

    0

    Led will glow

    1

    0

    1

    Led will glow

    1

    1

    0

    Led will glow

    1

    1

    1

    Led will not glow

    0

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