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Chemistry Test - 1

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Chemistry Test - 1
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  • Question 1
    1 / -0

    When propyne is treated with CH3MgX, the product formed is:

    Solution

    The triple bond of alkyne has high electron density that attracts the H's electrons. The strongly basic Grignard will combine with this H. So, the CH3(-) MgBr would become CH4  combination with H+.

    Hence the correct answer is option (a).

  • Question 2
    1 / -0
    One mole of a complex compound Co(NH3)5Cl3 gives 3 moles of ions on disssolution in water. One mole of the same complex reacts with two moles of AgNO3 solution to yield two moles of AgCl (s). The structure of the complex is
    Solution

    \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}+\mathrm{AgNO}_{3} \longrightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right]\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{AgCl}_{2}\)

    The complex is \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\)

    Hence the correct answer is option (a).

  • Question 3
    1 / -0

    Why do boron and aluminium halides behave as Lewis acids?

    Solution

    ∵ Lewis acid is defined as an electron-pair acceptor and both boron and aluminium in their tri-halides (MX3) possess six electrons in their valence shell. 

    Hence, to complete their octet, they can accept a lone pair of electrons.

    Thus, both behave as Lewis acid.

    Hence the correct answer is option (a).

  • Question 4
    1 / -0
    Which of the following complexes is correctly named?
    Solution

    It is correctly named.

    [Cr(NCS)4(NH3)2]- : Diamminetetrathiocyanatochromate(III) ion

    Hence the correct answer is option (d).

  • Question 5
    1 / -0
    The minimum amount of iron required to produce just sufficient hydrogen (by reaction with dil. HCl) to react completely with the oxygen obtained by heating 2.45 g KClO3 is
    Solution

    2KClO3 \(\rightarrow\) 2KCl + 3O2

    \(\therefore\) 245 g KClO3 produces 3 moles oxygen or 2.45 g KClO3 gives 0.03 mole oxygen.

    2H2 + O2 \(\rightarrow\) 2H2O or 1 mole oxygen reacts with 2 moles hydrogen or 0.03 mole oxygen will react with 0.06 mole hydrogen.

    Fe + 2HCl \(\rightarrow\) FeCl2 + H2 or 1 mole hydrogen is obtained from 56 g Fe or 0.06 mole hydrogen will be obtained from 56 × 0.06 g Fe = 3.36 g Fe.

    The solution can also be obtained by the equivalent concept:

    \((G \cdot E q)_{K C l O_{3}}=(G. E q)_{F e}\)

    \((n \times N-\text {factor})_{K C l O_{3}}=(n \times N-\text {factor})_{F_{e}}\)

    \(\frac{2.45}{122.5} \times 6=n \times 2\)

    nFe required = 0.06

    Mass of Iron required = 0.06 × 56.0 = 3.36 g

    Hence the correct answer is option (b).

  • Question 6
    1 / -0

    Which of the following is true for the given reaction?

    2Al (s) + 6HCl (aq) \(\rightarrow\) 2Al3+ (aq) + 6Cl- (aq) + 3H2 (g)

    Solution

    For 6 moles of HCl, 3 moles of H2 is produced.

    So, for one mole, \(\frac{3}{6}\)mole of the H2 is produced.

    Hence, volume of H2 produced \(=\frac{1}{2} \times\) 22.4 = 11.2 litres

    33.6 litres of H2 (g) at STP is produced for every mole of Al that reacts. Hence, both the options (1) and (4) are incorrect.

    The volume ratio is same as the molar ratio only for gaseous species and not for aqueous solutions. Hence the option (3) is also incorrect.

    Hence the correct answer is option (b).

  • Question 7
    1 / -0
    Which of the following sets contains colourless aquated transition metal ions only?
    Solution

    Sc3+: 3d0, No unpaired electrons - Colourless

    Ti4+: 3d0, No unpaired electrons - Colourless

    Zn2+: 3d10, No unpaired electrons - Colourless

    Hence the correct answer is option (c).

  • Question 8
    1 / -0
    Consider an assumption that air contains 22.4% oxygen. How many moles of oxygen atoms are there in 1 litre of the air under standard conditions?
    Solution

    According to the given data:

    Volume of oxygen in \(1 L\) air \(=\frac{22.4}{100} \times 1 L=0.224 L\)
    Number of moles of \(O _{2}\) gas \(=\frac{\text {Given volume}}{\text {Molar volume}}=\frac{0.224}{22.4}=0.01\)
    Number of moles of 0 -atoms \(=2 \times n_{O_{2}}=2 \times 0.01=0.02\) moles
    Hence the correct answer is option (d).
  • Question 9
    1 / -0
    Match the following:
    Column – I
    Column – II
    A. Enthalpy 1. U + pV
    B. Helmholtz energy 2. H − T S
    C. Gibbs energy 3. U − T S
    Solution

    Enthalpy H is a function of state defined by the relation: H = U + pV.

    Helmholtz energy F is a function of state defined by the relation: F = U − T S.

    Gibbs energy (or the Gibbs function) G is a function of state defined by the relation: G = H − T S.

    Hence the correct answer is option (b).

  • Question 10
    1 / -0
    The correct IUPAC name of the complex [Co(en)3](NO3)2 is
    Solution

    Correct IUPAC name of the complex [Co(en)3](NO3)2 is tris(ethylenediamine)cobalt(II) nitrate..

    Hence the correct answer is option (d).

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