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Chemistry Test - 12

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Chemistry Test - 12
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  • Question 1
    4 / -1

    The total number of ions present in 111 g of CaCl2 is:

    Solution

    Molecular weight of

    CaCl2 = 111 g/mol

    Ions in one calcium chloride molecule = Ca+2 + 2Cl

    = 3 ions

    Now no. of molecules in 111 g/mol of CaCl2 = Avogadros number

    = 6.02 × 1023 molecules

    So number of ions in 111 g/mol of CaCl2

    = 3 × 6.02 × 1023 ions

    = 3 moles.

  • Question 2
    4 / -1

    Which of the following is not an actinoid?

    Solution

    Terbium (Z \(= 65\)) is a lanthanide and all others are actinoids.

    • Lanthanides have atomic numbers from \(58\) to \(71\).
    • Actinides have atomic numbers from \(90\) to \(103\).
    • The lanthanides and actinides form a group that appears almost disconnected from the rest of the periodic table.
    • This is the f- block of elements, known as the inner transition series. This is due to the proper numerical position between Groups \(2\) and \(3\) of the transition metals.
  • Question 3
    4 / -1

    Which of the following is used as catalytic promoter?

    Solution

    Promoters are the substances which when mixed with catalysts speed up the reaction.

    Promoters are not capable of catalyzing a reaction alone but when mixed with catalysts, increases the efficiency of the catalysts.

    Promoters increase the catalytic surface area and thus increases the efficiency of the catalysts.

    For example, Molybdenum used in small amounts with Iron in Haber's Process increases the efficiency of finely divided iron.

    Chromic oxide Cr2O3 is used as a promoter in water gas shift reaction with the catalyst Zinc Oxide.

    Promoters are also known as Activators.

    Nitrogen gas is extremely inert in nature and is used as a protective gas in many reactions to offer an inert environment for the reaction to occur.

    Nitrogen is seen to act as a promoter in many reactions and promote the activity of Ru clusters.

     It is now seen that Nitrogen can be activated in much less severe conditions.

    Helium, Chlorine, and Sulphur are not used as promoters.

    Nitrogen is used as a catalytic promoter.

  • Question 4
    4 / -1

    Which of the following properties are similar for isotopes?

    Solution

    Isotopes have same atomic numbers but different mass numbers. This also means that the isotopes have the same number of electrons.

    Chemical properties are determined by electronic configuration. So, with the same electronic configuration, they have similar chemical properties.

  • Question 5
    4 / -1

    The ionisation enthalpy of noble gases is_____________.

    Solution

    The ionisation enthalpy of noble gases is very high as noble gases posses complete valence shell configurations. Hence energy required to remove an electron from valence shell of noble gas is the highest in a period.

    Ionization enthalpy of an element can be defined as the amount of energy required to remove an electron from an isolated gaseous atom in its gaseous state.

    Helium has the largest first ionization energy, while francium has one of the lowest.

  • Question 6
    4 / -1

    The final product \((C)\) obtained in the reaction sequence is \(C H_{3} C H_{2} C O O H \stackrel{P C l_{3}}{\longrightarrow}(A) \frac{C_{6} H_{6}}{A l C l_{3}}(B) \frac{N H_{2} N H_{2}}{\text { base, heat }}(C)\).

    Solution

    The reaction obtained is as follows:

  • Question 7
    4 / -1

    Detergents are prepared by the action of \(H_2SO_4\) on which of the following?

    Solution

    Detergents are prepared by the action of \(H_2SO_4\) on Lauryl alcohol.Dodecanol, or lauryl alcohol is an organic compound produced industrially from palm kernel oil or coconut oil. It is a fatty alcohol. Sulfate esters of lauryl alcohol specially sodium alcohol lauryl sulfate are very widely used as surfactants.

    The chemical reaction is given as,

    \(\underset{\text{Lauryl alcohol}}{\mathrm{CH} _3(\mathrm{CH} _2) _{10} \mathrm{CH} _2 \mathrm{OH}}+\mathrm{H} _2 \mathrm{SO} _4 \rightarrow \underset{\text{Lauryl hydrogen alcohol}}{\mathrm{CH} _3(\mathrm{CH}_ 2) _{10} \mathrm{CH} _2 \mathrm{OSO} _3 \mathrm{H}} ~{\overset{NaOH}{\longrightarrow}}~ \underset{\text{Anionic detergent}}{\mathrm{CH} _3(\mathrm{CH}_ 2)_{ 10 }\mathrm{CH}_ 2 \mathrm{OSO} _3-\mathrm{Na}^+}\)

  • Question 8
    4 / -1

    Which of the following statements are correct statement(s) about pyrophosphoric acid(\(\left.{H}_{4} {P}_{2} {O}_{7}\right)\)?

    Solution

    Structure of \(\mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7}\) is shown in figure. Oxidation state of \(\mathrm{P}\) is +5 and it has one \(\mathrm{P}-\mathrm{O}-\) P bond.

  • Question 9
    4 / -1

    The heat change associated with reactions at constant volume is due to the difference in which property of the reactants and the products?

    Solution

    The heat change associated with reactions at constant volume is due to the difference in the internal energy of the reactants and the products.

    First Law of Thermodynamics dictates that \(\Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{W}\)

    At constant \(\mathrm{V}, \Delta \mathrm{W}=0\)

    So, \(\Delta \mathrm{Q}=\Delta \mathrm{U}\)

    So at constant volume, heat change takes place due to a change in the internal energy of the system.

  • Question 10
    4 / -1

    Of the following the most acidic is:

    Solution

    All the elements of the group 15 elements form tri oxides and pentoxides having the general formula M2O3 or M2O5.

    The oxides of Nitrogen, Phosphorus, and Arsenic are acidic.

    The trioxide of antimony Sb2O3 is amphoteric while that of bismuth Bi2O3 is basic.

    As2O3 is acidic in nature.

    The pentoxides of all these elements are acidic but acidic character decreases down the group.

    Thus, P2O5 is the strongest acidic oxide whereas Bi2O3 is the weakest acidic oxide.

    The acidic character of the same element increases with an increase in the oxidation state.

    Thus, the most acidic oxide among the following is P2O5.

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