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Chemistry Test - 7

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Chemistry Test - 7
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  • Question 1
    4 / -1

    The law, which states that at constant temperature, the volume of a given mass of gas is inversely proportional is pressure, is known as:

    Solution

    The law, which states that at constant temperature, the volume of a given mass of gas is inversely proportional is pressure, is known as Boyles law. As per Boyle's law, any change in the volume occupied by a gas (at constant quantity and temperature) will result in a change in the pressure exerted by it. In other words, the product of the initial pressure and the initial volume of a gas is equal to the product of its final pressure and final volume (at constant temperature and number of moles). This law can be expressed mathematically as follows:

    \(P_{1} V_{1}=P_{2} V_{2}\)

    Where,

    - \(P_{1}\) is the initial pressure exerted by the gas

    - \(V_{1}\) is the initial volume occupied by the gas

    - \(P_{2}\) is the final pressure exerted by the gas

    - \(V_{2}\) is the final volume occupied by the gas

  • Question 2
    4 / -1

    The number of electrons, protons andneutrons in a species are equal to \(18\), \(16\)and \(16\) respectively. Assign the propersymbol to the species.

    Solution

    The atomic number is equal tonumber of protons \(= 16\). The element issulphur (S).

    Atomic mass number \(=\) number ofprotons \(+\) number of neutrons

    \(= 16 + 16 = 32\)

    Species is not neutral as the number ofprotons is not equal to electrons. It isanion (negatively charged) with chargeequal to excess electrons \(= 18 – 16 = 2\)

    Thus symbol is \({ }_{16}^{32} \mathrm{~S}^{2-}\).

  • Question 3
    4 / -1

    What happens with ionic radii of group \(17\) elements, as we go down the group?

    Solution

    The atomic and ionic radii increase as the atomic number increases. This is because the number of electron shells has increased. As the halogen atom forms the halide ion by gaining one electron, so radius of the halide ion is always greater than that of the corresponding halogen atom.

  • Question 4
    4 / -1

    Positive Beilstein shows that:

    Solution

    Positive Beilstein shows that halogens may be present. A positive Beilstein’s test for halogens does not always indicate the presence of halogen since some halogen-free compounds viz. urea, thiourea, amides etc. also respond this test. The reason being the fact that these halogen-free compounds form cuprous cyanide which is volatile and decomposes to copper which burns with green flame.

  • Question 5
    4 / -1

    A complex has the molecular formula \(\mathrm{Co} .5 \mathrm{NH}_{3} . \mathrm{NO}_{2} . \mathrm{Cl}_{2}\). One mole of this complex produces three moles of ions in an aqueous solution. On reacting this solution with excess of \(\mathrm{AgNO}_{3}\) solution, we get 2 moles of white ppt. The complex is:

    Solution

    A complex has the molecular formula \(\mathrm{Co} .5 \mathrm{NH}_{3} . \mathrm{NO}_{2} . \mathrm{Cl}_{2}\). One mole of this complex produces three moles of ions in an aqueous solution. On reacting this solution with excess of \(\mathrm{AgNO}_{3}\) solution, we get 2 moles of white ppt. The complex is\(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}\).

    \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right] \mathrm{Cl}_{2}\) can form three ions, one \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{2}\right]^{2+}\) and two \(\mathrm{Cl}^{-}\)ions.

    As 1 mole of complex gives 2 moles of \(\mathrm{Cl}^{-}\)ions, 2 moles of AgCI will be precipitated.

  • Question 6
    4 / -1

    Which of the following artificial sweeteners can be only used in soft drinks?

    Solution

    Aspartamecan be only used in soft drinks. It is an artificial sweetening agent which is unstable at higher temperatures. It is a compound formed from aspartic acid and phenylalanine. It is 100 times as sweet as cane sugar.

  • Question 7
    4 / -1

    Glycogen is a polymer of:

    Solution

    Glycogen is a polymer of glucose. Glycogen is a substance which is deposited in body tissues in the form of carbohydrates and it is broken down in the form of glucose which provides an instant source of energy to muscles by the process of glycolysis. It is accumulated in response to insulin and it is broken down into glucose in response to glucagon and it is mainly stored in the liver and the muscles. It provides the body with an instant source of energy when the blood glucose level decreases. It maintains blood glucose level and it is really important because glucose is the only fuel used by the brain virtually.

  • Question 8
    4 / -1

    If we have an element with atomic number 115, then which of the following statements is correct about this element?

    Solution

    If we place an element with atomic number 115 in the periodic table, it will come under the 15th group. So, it will be a p-block element.

  • Question 9
    4 / -1

    The rate of a first order reaction is \(1.5 \times 10^{-2} M {~min}^{-1}\) at \(0.5 {M}\) concentration of the reactant. The half-life of the reaction is:

    Solution

    We know that for a first order reaction:-

    Rate = k[R]

    \(\therefore 1.5 \times 10^{-2} \mathrm{M} \min ^{-1}=\mathrm{k}[0.5 \mathrm{M}]\)

    \(\Rightarrow \mathrm{k}=\frac{1.5 \times 10^{-2} \mathrm{M} / \mathrm{min}}{0.5 \mathrm{M}}\)

    \(\Rightarrow \mathrm{k}=0.03 \mathrm{~min}^{-1}\)

    We also know that, half life of a first order reaction:

    \(\mathrm{t} \frac{1 } 2=\frac{ln (2)}{\mathrm{k}}\)

    \(=\frac{0.693}{\mathrm{k}}\)

    \(=\frac{0.693}{0.03 \mathrm{~min}^{-1}}\)

    \(=23.1 \) min

  • Question 10
    4 / -1

    Which among the following is an example of a saturated carbon compound?

    Solution

    Ethane is an example of a saturated carbon compound.Saturated hydrocarbons are carbon compound that contains only single bonds between carbon atoms.Ethane is a colourless, odourless gas.Ethane is isolated on an industrial scale from natural gas and as a petrochemical by-product of petroleum refining.The chemical formula of Ethane is \(\mathrm{C}_{2} \mathrm{H}_{6}\).Ethane can be found underground in liquid form in rock formations.

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