Electrochemistry Test

Result

Electrochemistry Test - 28

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Weekly Quiz Competition

Question 1
4 / -1

From the solution of an electrolyte, one mole of electron will deposit at cathode.

A
63.5 gm of Cu

B
24 gm of Mg

C
11.5 gm of Na

D
9.0 gm of Al
Question 2
4 / -1

When an electric current is passed through acidulated water, 112 ml of hydrogen gas at NTP is collected at the cathode in 965 seconds.The current passed in amperes, is

A
1.0

B
0.5

C
0.1

D
2.0

Solution
Question 3
4 / -1

The charge required to librerate 11.5 g sodium from fused sodium chloride is

A
0.5 faraday

B
1.0 faraday

C
1.5 faraday

D
96500 coulombs

Solution
Question 4
4 / -1

How long will it take for a current of 3 amperes to decompose 36 g of water ? ( Eq. wt of hydrogen is 1 and that of oxygen 8)

A
36 hours

B
18 hours

C
9 hours

D
4.5 hours

Solution
Question 5
4 / -1

What is the amount of chlorine evolved when 2 amperes of current is passed for 30 minutes in an aqueous solution of NaCl ?

A
66 g

B
1.32 g

C
33 g

D
99 g

Solution
Question 6
4 / -1

The same amount of electricity was passed through two separate electrolytic cells containing solutions of nickel nitrate and chromium nitrate respectively. If 0.3 g of nickel was deposited in the first cell, the amount of chromium deposited is (At wt. Ni = 59, Cr = 52)

A
0.1 g

B
0.17 g

C
0.3 g

D
0.6 g

Solution
Question 7
4 / -1

How much quanitity of electricity has to be passed through 200 ml of 0.5 M CuSO₄ solution to completely deposit copper

A
96500 C

B
2 × 9650C

C
2 × 96500C

D
4 × 96500C

Solution
Question 8
4 / -1

Time required to deposit one millimole of aluminium metal by the passage of 9.65 amperes through aqueous solution of aluminium ions is

A
30 s

B
10 s

C
30,000s

D
10,000 s

Solution
Question 9
4 / -1

A
– 0.35 V

B
0.35 V

C
1.17 V

D
– 1.17 V

Solution
Question 10
4 / -1

The standard reduction potential for Fe²⁺/Fe and Sn²⁺/Sn electrodes are ‒ 0.44 and ‒ 0.14 volt respectively. For the cell reaction : Fe²⁺ + Sn → Fe + Sn²⁺, the standard emf is

A
+ 0.30 V

B
‒ 0.58 V

C
+0.58 V

D
‒ 0.30 V

Solution