Redox Reaction & Volumetric Analysis Test

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Redox Reaction & Volumetric Analysis Test - 2

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Weekly Quiz Competition

Question 1
1 / -0

Statement-1: Oxidation state of hydrogen is +1 in H₂O while -1 in CaH₂.

Statement-2: CaH₂ is a metal hydride and for hydrides, hydrogen is assigned the oxidation number of -1.

A
Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

B
Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1.

C
Statement-1 is true but Statement-2 is false.

D
Statement-1 is false but Statement-2 is true.

Solution

Oxidation number of elements in their compounds or ions is obtained using some rules for e.g. hydrogen is assigned oxidation number of +1 in general and -1 for metal hydrides.
Question 2
1 / -0

In which of the following reactions, nitrogen undergoes change in oxidation state?

A
2NO₂+ H₂O → HNO₃+ HNO₂

B
2NO₂→ N₂O₄

C
N₂O₅+ H₂O → 2HNO₃

D
NH₃+ H₂O → NH⁺₄+ OH^-

Solution

2NO₂+ H₂O → HNO₃+ HNO₂

Oxidation Number of N changes from +4 (in NO₂) to +5 (in HNO₃) and +3 in HNO₂.
Question 3
1 / -0

Iron has lowest oxidation state in

A
Fe ( CO )₅

B
K₄[ Fe ( CN )₆]

C
K₃[ Fe( CN )₆]

D
FeSO₄.( NH₄)₂SO₄.6H₂O

Solution

Oxidation Number of Fe in
K₃[ Fe ( CN )₆] = + 3
FeSO₄.( NH₄)₂SO₄.6H₂O = +2
K₄[ Fe( CN )₆] = +2
Fe ( CO )₅ = 0
Question 4
1 / -0

In the reaction, Cl₂ + 2OH^-→ OCl^-+ Cl^- + H₂O

A
OH^– is both oxidizing and reducing agent

B
OH^– is oxidizing and Cl₂ is reducing agent

C
Cl₂ is both oxidizing and reducing agent

D
Cl₂ is oxidizing and OH^– is reducing agent

Solution

Oxidation Number of Cl₂ changes from 0 to +1 and –1.
Question 5
1 / -0

In Fe(II)-MnO₄^– titration, HNO₃ is not used because

A
it reduces Fe³⁺ formed

B
it oxidises Fe²⁺

C
it oxidises Mn²⁺

D
it reduces MnO₄^–

Solution

It oxidises Fe²⁺ to Fe³⁺ similar to KMnO₄.
Question 6
1 / -0

Statement-1: Oxidation number of carbon in CH₂O is zero.

Statement-2: CH₂O, formaldehyde, is a covalent compound.

A
Statement-1 is true but Statement-2 is false.

B
Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

C
Statement-1 is false but Statement-2 is true.

D
Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1.

Solution

Oxidation number can be calculated using some rules. H is assigned +1 oxidation state and O has oxidation number -2.

∴ O.No.ofCinCH₂O

O.No. of C + 2 (+1) + (-2) = 0

∴ O.No.of C = 0

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Re-Attempt Weekly Quiz Competition

Redox Reaction & Volumetric Analysis Test - 2

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Redox Reaction & Volumetric Analysis Test - 2

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Question 1

Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1.

Statement-1 is true but Statement-2 is false.

Statement-1 is false but Statement-2 is true.

Solution

Question 2

2NO2 + H2O → HNO3 + HNO2

2NO2 → N2O4

N2O5 + H2O → 2HNO3

NH3 + H2O → NH+4 + OH-

Solution

Question 3

Fe ( CO )5

K4 [ Fe ( CN )6 ]

K3 [ Fe( CN )6 ]

FeSO4.( NH4 )2 SO4.6H2O

Solution

Question 4

OH– is both oxidizing and reducing agent

OH– is oxidizing and Cl2 is reducing agent

Cl2 is both oxidizing and reducing agent

Cl2 is oxidizing and OH– is reducing agent

Solution

Question 5

it reduces Fe3+ formed

it oxidises Fe2+

it oxidises Mn2+

it reduces MnO4–

Solution

Question 6

Statement-1 is true but Statement-2 is false.

Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

Statement-1 is false but Statement-2 is true.

Both Statement-1 and Statement-2 are true and Statement-2 is not the correct explanation of Statement-1.

Solution

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2NO₂+ H₂O → HNO₃+ HNO₂

2NO₂→ N₂O₄

N₂O₅+ H₂O → 2HNO₃

NH₃+ H₂O → NH⁺₄+ OH^-

Fe ( CO )₅

K₄[ Fe ( CN )₆]

K₃[ Fe( CN )₆]

FeSO₄.( NH₄)₂SO₄.6H₂O

OH^– is both oxidizing and reducing agent

OH^– is oxidizing and Cl₂ is reducing agent

Cl₂ is both oxidizing and reducing agent

Cl₂ is oxidizing and OH^– is reducing agent

it reduces Fe³⁺ formed

it oxidises Fe²⁺

it oxidises Mn²⁺

it reduces MnO₄^–