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Classification of elements & Periodicity in properties Test - 3

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Classification of elements & Periodicity in properties Test - 3
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  • Question 1
    1 / -0

    Ionization potentials of the following elements are in the order

    Solution

    Leaving few exceptions, ionization potential decreases down the group.

    The correct answer is: Al≈Ga>Tl>ln

  • Question 2
    1 / -0

    Statement-1: Lattice energy in TiO2 will be much larger than in NaCl.

    Statement-2: The higher value of lattice energy for TiO2 as compared to that of NaCl is due to increased ionic charge.

    Solution

    Both assertion and reason are true and reason is the correct explanation of assertion.

    The correct answer is: Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

     

  • Question 3
    1 / -0

    The first ionization energies of Mg, Al, Si, P and S are in the order:

    Solution

    Removal of 3s2electron of Mg is more difficult than 3p3electron of Al. Also, removal of 3p3 electron of P requires greater energy than 2p4electron of S.

    The correct answer is: Al<Mg<Si<S<P

  • Question 4
    1 / -0

    Amongst the following, the incorrect statement is

    Solution

    The second ionization of Na requires much larger energy to break the stable configuration 2s2 2p6 than the energy required to remove 3s1 electron of Mg+.

    The correct answer is: The second ionization potential of Mg is greater than that of Na

     

  • Question 5
    1 / -0

    Statement-1: Li resembles Mg.

    Statement-2: Li+ has same size as Mg2+.

    Solution

    Li shows diagonal relationship with Mg. Reason is the correct explanation of Assertion.

    The correct answer is: Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanation of Statement-1.

     

  • Question 6
    1 / -0

    Identify the least stable amongst the following

    Solution

    Adding an electron to a full subshell (2s2 configuration of Be) is not favorable energetically.

    The correct answer is: Be

     

  • Question 7
    1 / -0

    The species that has the lowest ionization energy amongst the following is

    Solution

    Removal of 3p1 electron from Al requires lesser energy than that of 3s2 electron of Mg (full subshell and having greater penetration towards nucleus).

    The correct answer is: Al

     

  • Question 8
    1 / -0

    The element, with one of the following electronic configuration has the highest electron affinity (most positive value)

    Solution

    The configuration 3d54s2 is highly stable as d-subshell is half-filled and s-subshell is fully filled. It has no tendency to gain electron.

    The correct answer is: [Ar]3d54s2

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