Thermodynamics Test

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Thermodynamics Test - 21

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Weekly Quiz Competition

Question 1
4 / -1

Which of the following indicates the heat of reaction equal to heat of formation ?

A
C (graphite) + O₂ (1 atm) → CO₂ (1 atm)

B
C (diamond) + O₂ (1 atm) → CO₂ (2 atm)

C
C (graphite) + O₂ (1 atm) → CO₂ (2 atm)

D
C (diamond) + O₂ (1 atm) → CO₂ (1 atm)
Question 2
4 / -1

Calculate ∆H (in Joules) for, C (graphite) → C (diamond), from the following data
C (graphite) + O₂ (g) → CO₂ (g) ; ∆H = - 393.5 kJ
C (diamond) + O₂ (g) → CO₂ (g) ; ∆H = - 395.4 kJ

A
1900

B
- 788.9 × 10³

C
190000

D
+ 788.9 × 10³
Question 3
4 / -1

A
180 kJ mol^-1

B
360 kJ mol^-1

C
213 kJ mol^-1

D
425 kJ mol^-1
Question 4
4 / -1

The ∆H°_f for CO₂ (g), CO(g ) and H₂O (g) are - 393.5, -110.5 and - 241.8 kJ / mol respectively. The standard enthalpy change (in kJ) for the reaction
CO₂ (g) + H₂ (g) → CO (g ) + H₂O (g) is

A
524.1

B
41.2

C
- 262.5

D
- 41.2
Question 5
4 / -1

The value of ∆E for combustion of 16 g of CH₄ is - 885389 J at 298 K. The ∆H combustion for CH₄ in J mol^-1 at this temperature will be
(Given that, R = 8.314 JK^-1mol^-1)

A
- 55337

B
- 880430

C
- 885389

D
- 890348
Question 6
4 / -1

If the bond dissociation energies of XY, X₂ and Y₂ (all diatomic molecules) are in the ratio of 1:1:0.5 and ∆H_f for the formation of XY is -200 kJ mol^-1 . The bond dissociation energy of X₂ will be

A
400 kJ mol^-1

B
300 kJ mol^-1

C
20 kJ mol^-1

D
None of these

Solution
Question 7
4 / -1

For the reaction (at 1240 K and 1 atm.)
CaCO₃ (s) → CaO(s) + CO₂ (g)
∆H = 176 kJ /mol ; ∆E will be

A
160 kJ

B
165.6 kJ

C
186.4 kJ

D
180 kJ
Question 8
4 / -1

Minimum work is obtained when 1 kg of ... gas expanded under 500 kPa to 200 kPa pressure at 0°C.

A
chlorine

B
oxygen

C
nitrogen

D
methane

Solution
Question 9
4 / -1

Enthalpy of formation of HF and HCl are - 161 kJ and - 92 kJ respectively. Which of the following statements is incorrect ?

A
HCl is more stable than HF

B
HF and HCl are exothermic compounds

C
The affinity of fluorine to hydrogen is greater than the affinity of chlorine to hydrogen

D
HF is more stable than HCl
Question 10
4 / -1

A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If ∆H is the enthalpy change and ∆E is the change in internal energy, then

A
∆H > ∆E

B
∆H < ∆E

C
∆H = ∆E

D
the relationship depends on the capacity of the vessel

Solution

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Thermodynamics Test - 21

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Thermodynamics Test - 21

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Question 1

C (graphite) + O2 (1 atm) → CO2 (1 atm)

C (diamond) + O2 (1 atm) → CO2 (2 atm)

C (graphite) + O2 (1 atm) → CO2 (2 atm)

C (diamond) + O2 (1 atm) → CO2 (1 atm)

Question 2

1900

- 788.9 × 103

190000

+ 788.9 × 103

Question 3

180 kJ mol-1

360 kJ mol-1

213 kJ mol-1

425 kJ mol-1

Question 4

524.1

41.2

- 262.5

- 41.2

Question 5

- 55337

- 880430

- 885389

- 890348

Question 6

400 kJ mol-1

300 kJ mol-1

20 kJ mol-1

None of these

Solution

Question 7

160 kJ

165.6 kJ

186.4 kJ

180 kJ

Question 8

chlorine

oxygen

nitrogen

methane

Solution

Question 9

HCl is more stable than HF

HF and HCl are exothermic compounds

The affinity of fluorine to hydrogen is greater than the affinity of chlorine to hydrogen

HF is more stable than HCl

Question 10

∆H > ∆E

∆H < ∆E

∆H = ∆E

the relationship depends on the capacity of the vessel

Solution

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C (graphite) + O₂ (1 atm) → CO₂ (1 atm)

C (diamond) + O₂ (1 atm) → CO₂ (2 atm)

C (graphite) + O₂ (1 atm) → CO₂ (2 atm)

C (diamond) + O₂ (1 atm) → CO₂ (1 atm)

- 788.9 × 10³

+ 788.9 × 10³

180 kJ mol^-1

360 kJ mol^-1

213 kJ mol^-1

425 kJ mol^-1

400 kJ mol^-1

300 kJ mol^-1

20 kJ mol^-1