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Trignometry Test - 1

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Trignometry Test - 1
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  • Question 1
    1 / -0

    If cos4 θ + α, sin4 θ + α are the roots of the equation x2 + b (2x + 1) = 0 and cos2 θ + β, sin2 θ + β are the roots of the equation x2 + 4x + 2 = 0 then b is equal to

    Solution

    We have 
    cos4 θ - sin4 θ = cos2 θ - sin2 θ = cos2θ
    ⇒ (-2b)2 - 4b = (-4)2 - 4 × 2
    ⇒ b2 - b - 2 = 0 ⇒ b = -1,2

     

  • Question 2
    1 / -0

    If sin α, sin β and cos α are in G.P. Then roots of the equation x2 + 2x cot β + 1 = 0 are always

    Solution

    sin α, sin β, cos α are in G.P
    ⇒ sin2 β = sin α cos α 
    ⇒ cos 2β = 1 - sin 2α ≥ 0 

    Now the discriminant of the given equation is 
    4cot2 β - 4 = 4 cos 2β. cosec2 β ≥ 0 
    ⇒ Roots are always real

     

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