Applications of Derivatives Test

Result

Applications of Derivatives Test - 46

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

If the rate of increase of area of a circle is not constant but the rate of increase of perimeter is constant, then the rate of increase of area varies

A
As the square of the perimeter

B
Inversely as the perimeter

C
As the radius

D
Inversely as the radius

Solution
Question 2
4 / -1

A stone thrown vertically upwards rises ‘s’ metre in t seconds, where s = 80t – 16t², then the velocity after 2 second is

A
8 m/sec

B
16 m/sec

C
32 m/sec

D
64 m/sec

Solution
Question 3
4 / -1

A
2

B

C

D
–3

Solution
Question 4
4 / -1

The speed v of a particle moving along a straight line is given by a + bv² = x² (where x is its distance from the origin). The acceleration of the particle is

A

B

C

D

Solution
Question 5
4 / -1

A particle is moving along the curve x = at² + bt + c. If ac = b², then the particle would be moving with uniform

A
Rotation

B
Velocity

C
Acceleration

D
retardation

Solution
Question 6
4 / -1

The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. The rate at which the area increases, when the side is 10 cm is

A

B
10 sq. unit/sec

C

D

Solution
Question 7
4 / -1

The rate of the change of the surface area of a sphere of radius r when the radius is increasing at the rate of 2cm/sec is proportional to

A

B

C
r

D
r²

Solution
Question 8
4 / -1

Moving along the x - axis are two points with x = 10 + 6t; x = 3 + t². The speed with which they are reaching from each other at the time of encounter is (x is in cm and it is in seconds)

A
16 cm/sec

B
20 cm/sec

C
8 cm/sec

D
12 cm/sec

Solution
Question 9
4 / -1

The position of a point in time ‘t’ is given by x = a + bt – ct², y = at + bt². Its acceleration at time ‘t’ is

A
b – c

B
b + c

C
2b – 2c

D

Solution
Question 10
4 / -1

Gas is being pumped into a spherical balloon at the rate of 30 ft³/min. Then the rate at which the radius increases when it reaches the value 15 ft. is

A

B

C

D

Solution