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Binomial Theore...

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    Let P(n) denote the statement that n2 + n is odd. It is seen that P(n) ⇒ P(n + 1), Pn is true for all

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    If P(n) = 2 + 4 + 6 + ... + 2n, n ∈ N, then P(k) = k(k + 1) + 2 ⇒ P(k + 1) = (k + 1) (k + 2) + 2 for all k ∈ N. So we can conclude that P(n) = n(n + 1) + 2 for

  • Question 10
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    The fourth term in the expansion of (1 - 2x)3/2 will be

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