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3D Geometry Test - 1

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  • Question 1
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    Let A (1, - 1, 1) and B (- 1, 1, -1) be the vertices of triangle ABC such that ∠A = ∠B
    Locus of the vertex C is

    Solution

    Let coordinate of C be ( α, β, γ )

    As AC = BC 

    ( α - 1 )2 + ( β + 1 )2 + ( γ - 1 )2 = ( α + 1 )2 + ( β - 1 )2 + ( y + 1 )2

    locus of C is x - y + z = 0

     

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