Chemistry Test 170

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Chemistry Test 170

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Weekly Quiz Competition

Question 1
4 / -1

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g. of CO2. The empirical formula of the hydrocarbon is:

A

B

C

D

Solution
Question 2
4 / -1

Of the following sets which one does NOT contain isoelectronic species?

A

B

C

D

Solution
Question 3
4 / -1

Which one of the following has largest ionic radius?

A
Li⁺

B

C
B³⁺

D
F^-

Solution

On moving along a period ionic radii decreases due to increase in effective nuclear charge.
Question 4
4 / -1

Hybridisation of the underline atom changes in:

A

B

C

D

Solution
Question 5
4 / -1

For 1 mol of an ideal gas at a constant temperature T, the plot of (log P) against (log V) is a (P : Pressure, V : Volume)

A
Straight line parallel to x-axis.

B
Straight line with a negative slope.

C
Curve starting at origin.

D
Straight line passing through origin.

Solution

According to Boyle's law, PV = constant

∴ log P + log V = constant

log P = - log V + constant

Hence, the plot of log P vs log V is straight line with negative slope.
Question 6
4 / -1

The standard enthalpies of formation of and glucose(s) at 25°C are –400 kJ/mol, –300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25°C is

A
+2900 kJ

B
–2900 kJ

C
–16.11 kJ

D
+16.11 kJ

Solution
Question 7
4 / -1

In a saturated solution of the sparingly soluble strong electrolyte AgIO₃ (molecular mass = 283) the equilibrium which sets is If the solubility product constant Ksp of AgIO₃ at a given temperature is what is the mass of contained in 100 ml of its saturated solution?

A

B

C

D

Solution
Question 8
4 / -1

H₂S acts only as a reducing agent while SO₂ can act both as a reducing and oxidizing agent because

A
oxygen is more – ve in SO₂

B
hydrogen in H₂S is more + ve than oxygen

C
S in SO₂has one oxidation state

D
S in H₂S has –2 oxidation state

Solution

H₂S, the oxidation state of S is - 2. So it cannot accept more electrons because on accepting 2 electrons S acquires a noble gas configuration. So, it can acts only as a reducing agent by loosing electron. On the other hand, the oxidation state of S in SO₂ is + 4 which is an intermediate oxidation state of sulphur so it can reduce as well oxidise.
Question 9
4 / -1

Which of the following statements in relation to the hydrogen atom is correct?

A
3s, 3p and 3d orbitals all have the same energy

B
3s and 3p orbitals are of lower energy than 3d orbital

C
3p orbital is lower in energy than 3d orbital

D
3s orbital is lower in energy than 3p orbital

Solution

A hydrogen atom has only one electron, that experiences no shielding from other electrons, and therefore its energy level only depends on its distance away from the nucleus, which is dependent on its value of (n).

Therefore, the orbitals of a hydrogen atom increase energy as follows:

1s<2s=2p<3s=3p=3d<4s=4p=4d=4f<.....
Question 10
4 / -1

The melting point of lithium (181°C) is just double the melting point of sodium (98°C) because

A
down the group, the hydration energy decreases

B
down the group, the ionization energy decreases

C
down the group the cohesive energy decreases

D
None of these

Solution

The atom becomes larger on descending the group, so the bonds becomes weaker (metallic bond), the cohesive force/energy decreases and accordingly melting point also decreases.