Chemistry Test 20

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Chemistry Test 20

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Weekly Quiz Competition

Question 1
4 / -1

Consider the ground state of Cr atom (Z = 24). The number of electrons with the azimuthal quantum numbers I =1 and 2 are respectively

A
12 and 4

B
16 and 5

C
16 and 4

D
12 and 5

Solution

24 --→ 1s²2s²2p⁶3s²3p⁶4s¹3d⁵
l = 1 → p --→ 12
l = 2 → d --→ 5
Question 2
4 / -1

Which of one of the following pairs of molecules will have permanent dipole moments for both members?

A
SiF₄ and NO₂

B
NO₂ and CO₂

C
NO₂ and O₃

D
SiF₄ and CO₂

Solution

NO₂ an O₃ both are having irregular geometry.
Question 3
4 / -1

Which among the following factors is most important in making fluorine the strongest oxidizing halogen?

A
Electron affinity

B
Bond dissociation energy

C
Hydration enthalpy

D
Ionization enthalpy

Solution

Flourine has the highest hydration enthalpy which compensates for high bond dissociation energy and therefore makes it easier for F2 to be reduced and corresponding species to be oxidised, making it the strongest oxidising agent.

The reason for high hydration enthalpy could be attributed to small size and therefore higher charge density which interacts very strongly with water.
Question 4
4 / -1

Which of the following statement is wrong?

A
The stability of hydride increases from NH₃ to BiH₃ in group 15 of the periodic table.

B
Nitrogen cannot from dπ - pπ bond.

C
Single N – N bond is weaker than the single P – P bond.

D
N₂O₄ has two resonance structures.

Solution

As we move down the group, tendency to from covalent bond with small H decreases hence M-H bond enthalpy decreases.
Question 5
4 / -1

The actinoides exhibit more number of oxidation states in general than the lanthanoids. This is because

A
the actinoids are more reactive than the lanthanoids

B
the 5f orbitals extend further from the nucleus than the 4f orbitals

C
the 4forbitalsare more buried than the 4f orbitals

D
there is a similarity between 4f and 5f orbitals in their angular part of the wave function

Solution

The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because the 5f orbitals extend further from the nucleus than the 4f orbitals.
Question 6
4 / -1

Acid catalyzed hydration of alkenes except ethene leads to the formation of

A
primary alcohol

B
secondary or tertiary alcohol

C
mixture of primary and secondary alcohols

D
mixture of secondary and tertiary alcohols

Solution

For alkenes other than ethane, addition follows Markonikov’s rule. Hence they give either secondary or tertiary alcohols.

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Chemistry Test 20

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Chemistry Test 20

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Question 1

12 and 4

16 and 5

16 and 4

12 and 5

Solution

Question 2

SiF4 and NO2

NO2 and CO2

NO2 and O3

SiF4 and CO2

Solution

Question 3

Electron affinity

Bond dissociation energy

Hydration enthalpy

Ionization enthalpy

Solution

Question 4

The stability of hydride increases from NH3 to BiH3 in group 15 of the periodic table.

Nitrogen cannot from dπ - pπ bond.

Single N – N bond is weaker than the single P – P bond.

N2O4 has two resonance structures.

Solution

Question 5

the actinoids are more reactive than the lanthanoids

the 5f orbitals extend further from the nucleus than the 4f orbitals

the 4forbitalsare more buried than the 4f orbitals

there is a similarity between 4f and 5f orbitals in their angular part of the wave function

Solution

Question 6

primary alcohol

secondary or tertiary alcohol

mixture of primary and secondary alcohols

mixture of secondary and tertiary alcohols

Solution

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SiF₄ and NO₂

NO₂ and CO₂

NO₂ and O₃

SiF₄ and CO₂

The stability of hydride increases from NH₃ to BiH₃ in group 15 of the periodic table.

N₂O₄ has two resonance structures.