Chemistry Test 210

sp³d² hybridisation confirms to octahedral or square bipyramidal configuration.

Therefore, all the bond angles are 90° in the structure.

Ferric hydroxide forms a positive sol and thus, the anion of the electrolyte is the active ion, required to coagulate it. The coagulating power will be in the order of the net negative charge on the ions

Cl^- < SO₄^2- < PO₄^3- < [Fe(CN)₆]^4-

The paramagnetic substances are those which are freely magnetised when placed in a magnetic field. All the species which have unpaired electrons, are paramagnetic. When placed in a magnetic field, the domains of the unpaired electrons get aligned in the same direction.

KO₂, the superoxide of potassium, is paramagnetic because it has unpaired electrons.

SiO₂, TiO₂ and BaO₂ are all diamagnetic, as they have paired electrons.
 

When sulphur reacts with chlorine in the ratio 1 : 2, then SCI₄ is obtained, which on hydrolysis gives sulphurous acid (H₂SO₃).

Most alkenes react readily with ozone (O₃) in the process called ozonisation, even at low temperatures, to yield cyclic peroxidic derivatives known as ozonides.

For example,

The ozonides can be converted by hydrolysis to give aldehydes and ketones and hydrogen peroxide.

The products of ozonolysis of But-2-ene are ethanal and hydrogen peroxide.

In this process, H_,O is oxidised to H₂O₂.

In this reaction, SO₂CI₂ causes free radical substitution at benzylic position and alc. KOH causes elimination.

The statement (D) is incorrect. Fructose is a ketohexoses and is not oxidised by mild oxidising agents, like chlorine or bromine water.

All the other statements are correct.

(A) The anomeric carbon in sucrose is involved in the glycosidic linkage that links glucose and fructose and does not have a free OH group to undergo oxidation. Hence, sucrose is non-reducing.

(B) With bromine water, glucose is oxidised to gluconic acid.

(C) Glucose is dextrorotatory and rotates the plane polarised light in the clockwise direction.