Chemistry Test 39

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Chemistry Test 39

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Weekly Quiz Competition

Question 1
4 / -1

When CH₂ = CH – COOH is reduced with LiAlH₄, the compound obtained will be

A
CH₃ – CH₂ – COOH

B
CH₂ = CH – CH₂OH

C
CH₃ – CH₂ – CH₂OH

D
CH₃ – CH₂ – CHO

Solution

LiAlH₄ reduces –COOH to –CH₂OH without affecting C = C bond.
Hence, option B is correct.
Question 2
4 / -1

Consider the reaction, 2A + B → Products When concentration of B alone was doubled, the half-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

A
mol L^–1s^–1

B
s^–1

C
L mol^–1 s^–1

D
no unit

Solution

2A + B → Product
When conc. of B is doubled, the half life did not change, hence reaction is of first order w.r.t. B.
When concentration of A is doubled, reaction rate is doubled, hence reaction is of first order w.r.t. A.
Hence over all order of reaction is 1 + 1 = 2
So, unit of rate constant mol^–1 lit s^–1.
Hence, option C is correct.
Question 3
4 / -1

Which among the following will be named as dibromido-bis(ethylene diamine)chromium(III)bromide?

A
[Cr(en)₃]Br₃

B
[Cr(en)₂Br₂]Br

C
[Cr(en)Br₄]

D
[Cr(en)Br₂]Br

Solution

Dibromido means the presence of two anionic ligand(Br^-). Br^- is an anionic ligand as it possess negative charge.
Prefixes like bis,tris etc are used for complex ligands such as ethylene diamine(en).

1.[Cr(en)₃]Br₃
Here,the number of en groups present is three ,thus the prefix used will be tris instead of bis given in the name of the complex in the question.Thus option one is ruled out.
2.[Cr(en)₂Br₂]Br
The number of en groups present here is two .Thus the prefix used is bis. Moreover two Br ligands are present and thus is named di bromo.
The oxidation state of Chromium is +3 in the complex.Thus the complex given in option 2 is correct.
3. [Cr(en)Br₄]
The number of en group is one here and the oxidation state of Chromium is +4.Hence this option is ruled out.
4.[Cr(en)Br₂]Br
The number of en groups is also one and thus the given option is ruled out.
Hence, option B is correct.
Question 4
4 / -1

Which of the following statement about low density polythene is FALSE?

A
Its synthesis requires dioxygen or a peroxide initiator as a catalyst

B
It is used in the manufacture of buckets, dust-bins etc.

C
Its synthesis requires high pressure

D
It is a poor conductor of electricity

Solution

High density polythene is used for manufacturing buckets and dustbins.

Hence option B is correct.
Question 5
4 / -1

The substance not likely to contain CaCO₃ is

A
a marble stature

B
calcined gypsum

C
sea shells

D
dolomite

Solution

Calcined gypsum does not contain CaCO₃ (that’s sulphate one).

Hence, option B is correct.

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Chemistry Test 39

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Chemistry Test 39

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Question 1

CH3 – CH2 – COOH

CH2 = CH – CH2OH

CH3 – CH2 – CH2OH

CH3 – CH2 – CHO

Solution

Question 2

mol L–1s–1

s–1

L mol–1 s–1

no unit

Solution

Question 3

[Cr(en)3]Br3

[Cr(en)2Br2]Br

[Cr(en)Br4]

[Cr(en)Br2]Br

Solution

Question 4

Its synthesis requires dioxygen or a peroxide initiator as a catalyst

It is used in the manufacture of buckets, dust-bins etc.

Its synthesis requires high pressure

It is a poor conductor of electricity

Solution

Question 5

a marble stature

calcined gypsum

sea shells

dolomite

Solution

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CH₃ – CH₂ – COOH

CH₂ = CH – CH₂OH

CH₃ – CH₂ – CH₂OH

CH₃ – CH₂ – CHO

mol L^–1s^–1

s^–1

L mol^–1 s^–1

[Cr(en)₃]Br₃

[Cr(en)₂Br₂]Br

[Cr(en)Br₄]

[Cr(en)Br₂]Br