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JEE Advanced Mix Test 14

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JEE Advanced Mix Test 14
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Weekly Quiz Competition
  • Question 1
    4 / -1

    Select the correct statement (s)

    Solution

  • Question 2
    4 / -1

    Statement-1 : The melting points of the various fluorides of xenon decrease in the order XeF2 > XeF4 > XeF6.

    Statement-2 : Xe – F bond length in XeF2, XeF4 and XeF6 decreases in the order XeF2 > XeF4 > XeF6.

    Solution

    S-1 : The melting point depends on the packing of the molecules. Symmetrical molecules are more closely packed as compared to unsymmetrical molecules. Hence symmetrical molecules will have higher melting points as compared to unsymmetrical molecules.

    S-2 : This may be owing to the increase in charge on xenon atom with increasing number of F atoms.

     XeF2 XeF4 XeF6   
     2.00   1.95  1.89

  • Question 3
    4 / -1

    Statement-1 : Ethers behave as bases in the presence of mineral acids.

    Statement-2 : It is due to the presence of lone pair of electrons on the oxygen atom.

    Solution

  • Question 4
    4 / -1

    The elements of group 1 describe, more clearly than any other group of elements, the effects of increasing the size of atoms or ions on the physical and chemical properties. The chemical and physical properties of the elements are closely related to their electronic structures and sizes. These metals are highly electropositive and thus form very strong bases, and have quite stable oxo-salts. In the manufacturing of sodium hydroxide, chlorine and sodium carbonate, the sodium chloride is used as starting material.

    Solution

    Basic strength of the oxides increase in the order Li2O < Na2O < K2O < Rb2O < Cs2O. The increase in basic strength is due to the decrease in I.E. and increase in electropositive character.The melting points of the halides decrease in the order NaF > NaCl > NaBr > NaI, as the size of the halide ion increases. The decrease in melting point is due to increase the covalent character with increase in the size of anion according to Fajan's rule.

  • Question 5
    4 / -1

    The elements of group 1 describe, more clearly than any other group of elements, the effects of increasing the size of atoms or ions on the physical and chemical properties. The chemical and physical properties of the elements are closely related to their electronic structures and sizes. These metals are highly electropositive and thus form very strong bases, and have quite stable oxo-salts. In the manufacturing of sodium hydroxide, chlorine and sodium carbonate, the sodium chloride is used as starting material.

    Which of the following acts as an oxidising as well as reducing agent ?

    Solution

    NaNO2 (sodium nitrite) acts both as oxidising agent and reducing agent because the nitrogen atom in it is in +3 oxidation state (+3 is intermediate oxidation state for nitrogen)

    Oxidising property : 2NaNO2 + 2KI + 2H2SO→ NaSO4 + K2SO4 + 2NO + 2H2O + I2

    Reducing property : NaNO2 + H2O2 → NaNO3 + H2O.

  • Question 6
    4 / -1

    The elements of group 1 describe, more clearly than any other group of elements, the effects of increasing the size of atoms or ions on the physical and chemical properties. The chemical and physical properties of the elements are closely related to their electronic structures and sizes. These metals are highly electropositive and thus form very strong bases, and have quite stable oxo-salts. In the manufacturing of sodium hydroxide, chlorine and sodium carbonate, the sodium chloride is used as starting material.

    Sodium hydroxide is manufacture by the electrolysis of brine solution. The reaction by-products are:

    Solution

  • Question 7
    4 / -1

    Match the entries in Column I with the correctly related characteritic(s) in Column II.

    Solution

    (A) Two oxygen atoms per tetrahedron are shared forming rings. They have general formula (SiO3)n2n-.
    Be3Al2[Si6O18], beryl.
    (B) Two oxygen atoms per tetrahedron are shared forming a chain of tetrahedron. They have general
    formula (SiO3)n2n-
    (C) One oxygen atom per tetrahedron is shared. They have general formula Si2O72- . Thortveitite.
    (D) Three oxygen atoms per tetrahedron are shared. They have general formula (Si2O5)n2- .
    Mica (muscovite).

  • Question 8
    4 / -1

    From a point P(1, 2) pair of tangent’s are drawn to a hyperbola ‘H’ in which one tangent to each arm of hyperbola. Equation of asymptotes of hyperbola H are √3x – y + 5 = 0 & √3x + y – 1 = 0 then eccentricity of ‘H’ is

    Solution

  • Question 9
    4 / -1

    Length of latus rectum of parabola which touches the line 3x + 4y + 7 = 0 having focus at (2, 3) and tangent at vertex passes through a point (1, 1), is

    Solution

  • Question 10
    4 / -1

    An ellipse whose focii are (2, 4) & (14, 9) and touches x-axis then its eccentricity is

    Solution

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