JEE Advanced Mix Test 7

Result

JEE Advanced Mix Test 7

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

In displacement method, the distance between object and screen is 96 cm. The ratio of length of two images formed by a convex lens placed between them is 4.84.

A
Ratio of the length of object to the length of shorter image is 11/5.

B
Distance between the two positions of the lens is 36 cm.

C
Distance of the lens from the shorter image is 30 cm.

D
All are correct

Solution
Question 2
4 / -1

Which of the following statements is/are correct about the refraction of light from a plane surface when light ray is incident in denser medium. [C is critical angle]

A
The maximum angle of deviation during refraction is π/2 – C, it will be at angle of incidence C.

B
The maximum angle of deviation for all angle of incidences is p – 2C, when angle of incidence is slightly greater than C

C
If angle of incidence is less than C then deviation increases if angle of incidence is also increased.

D
all are correct

Solution
Question 3
4 / -1

Statement-1 : A beam of white light enters the curved surface of a semicircular piece of glass along the normal. The incoming beam is moved clockwise (so that the angle q increases), such that the beam always enters along the normal to the curved side. Just before the refracted beam disappears, it becomes predominantly red.

Statement-2 : The index of refraction for light at the red end of the visible spectrum is more than at the violet end

A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

C
Statement-1 is True, Statement-2 is False

D
Statement-1 is False, Statement-2 is True

Solution

: a & b are constant of medium. The index of refraction for light at the red end

of the visible spectrum is lesser than at the violet end.Hence statement -2 is false
Question 4
4 / -1

Statement-1: A point object moves near the principal axis of a fixed spherical mirror along a straight line. Then the image formed by the spherical mirror also moves along a straight line.

Statement-2: For an incident ray on a fixed spherical mirror there is a fixed reflected ray. If a point object moves along this incident ray, its image will always lie on the given reflected ray. Further an incident ray may be drawn from the moving point object in its direction of velocity towards the mirror.

A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1

C
Statement-1 is True, Statement-2 is False

D
Statement-1 is False, Statement-2 is True

Solution

Draw an incident ray on the mirror and trace the corresponding reflected ray. If a point object moves along this ray,its image will always lies on the traced reflected ray. Hence when a point object moves near the principal axisof a fixed spherical mirror along a straight line, then its image formed by the spherical mirror also moves along
a straight line.Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.
Question 5
4 / -1

Directions For Questions

A monochromatic point source S of wavelength l = 5000√2 Å (in air) is placed at a distance d = 1 mm below the surface of transparent liquid as shown in figure. A very large screen is placed along y-axis at horizontal distance D = 1 metre from point source. The refractive index of liquid is √2 . ( Neglect partial reflection of rays from source S at liquid-air interface.)

...view full instructions

The y-coordinates of second order bright formed on the screen is

A
250 mm

B
500 mm

C
-250 mm

D
-500 mm

Solution

The critical angle is C = 45°

Hence all rays from S which are incident on interface at an angle of incidence greater than 45° are reflected back (and appear to come from S1) and fall on screen between OP. Light also directly falls on OP from S.

So Interference pattern is formed in region OP.Since waves from S do not under go phase change during reflection, We can take S and S1 to be coherent sources in same phase. Hence zero order bright is formed at y = 0
Question 6
4 / -1

Directions For Questions

A monochromatic point source S of wavelength l = 5000 √2 Å (in air) is placed at a distance d = 1 mm below the surface of transparent liquid as shown in figure. A very large screen is placed along y-axis at horizontal distance D = 1 metre from point source. The refractive index of liquid is√2 . ( Neglect partial reflection of rays from source S at liquid-air interface.)

...view full instructions

The region on screen where interference pattern is formed lies in

A
– ∞ < y < + a

B
– ∞ < y < 0

C
1(m) < y < 0

D
-1(m) < y < 0

Solution

The critical angle is C = 45°

Hence all rays from S which are incident on interface at an angle of incidence greater than 45° are reflectedback (and appear to come from S1) and fall on screen between OP. Light also directly falls on OP from S.

Interference pattern is formed in region OP.

Since waves from S do not under go phase change during reflection, We can take S and S1 to be coherent sources in same phase. Hence zero order bright is formed at y = 0.
Question 7
4 / -1

Directions For Questions

A monochromatic point source S of wavelength l = 5000√2 Å (in air) is placed at a distance d = 1 mm below the surface of transparent liquid as shown in figure. A very large screen is placed along y-axis at horizontal distance D = 1 metre from point source. The refractive index of liquid is√2 . ( Neglect partial reflection of rays from source S at liquid-air interface.)

...view full instructions

The minimum horizontal distance of screen from fixed source such that at least one bright is formed on screen

A
1 mm

B
2 mm

C
1 cm

D
1 m

Solution

The critical angle is C = 45°

Hence all rays from S which are incident on interface at an angle of incidence greater than 45° are reflected back (and appear to come from S1) and fall on screen between OP. Light also directly falls on OP from S.

Interference pattern is formed in region OP.

Since waves from S do not under go phase change during reflection, We can take S and S1 to be coherent sources in same phase. Hence zero order bright is formed at y = 0.
Question 8
4 / -1

A white light ray is incident on a glass prism, and it create four refracted rays A, B, C and D. Match the refracted rays with the colours given (1 & D are rays due to total internal reflection.):

A
(A) p, (B) r, (C) q, (D) s

B
(A) r, (B) p, (C) q, (D) s

C
(A) q, (B) s, (C) p, (D) r

D
(A) q, (B) p, (C) r, (D) s

Solution

By snell's law n = So at inclined face angular incidence is same for all ray and refraction is from denser to rarer. So emergent angle will be less for red.
Question 9
4 / -1

A

B

C

D

Solution
Question 10
4 / -1

A

B

C

D

Solution