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Mathematics Test 100

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  • Question 1
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    Let the subset  S of the set {1,2,3,4,5,6,7,8,9} be randomly formed such that sums of each unordered pair of distinct numbers from S are all different. Then the probability that number of elements in set S is greater than 5 is -

    Solution

    Smallest possible sum is 3 & largest possible sum is 17, that gives 15 possible sums from 3 to 17.

    If S has '6' elements then it has 

    6C2 = 15 different sums.

    ⇒ S contains 3 (1 + 2) also 17 (9 + 8) 

    But 1 + 9 = 2 + 8 

    ⇒ No 'S' containing 6 elements least.

    ⇒ Required probability = 0.

     

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