Mathematics Test 150

Result

Mathematics Test 150

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Weekly Quiz Competition

Question 1
4 / -1

A
1

B
2

C
1/2

D
None of these

Solution
Question 2
4 / -1

The solution of the differential equation

is

A

B

C

D
None of these

Solution
Question 3
4 / -1

For different values of K the straight lines given by the equation (2 + K)x + (1 + K)y = 5 + 7 K are always :-

A
Parallel

B
Passes through (2, –9)

C
Passes through (–2, 9)

D
Passes through (–2, –9)

Solution

Put K = –1 gives x = –2

and K = –2 gives y = 9

Hence lines always passes through (–2, 9)
Question 4
4 / -1

The line 2x – y + 1 = 0 is tangent to the circle at the point (2, 5) and the centre of the circle lies on x – 2y = 4. The radius of the circle is:-

A
3√5

B
5√3

C
2√5

D
5√2

Solution
Question 5
4 / -1

A line passes through P(–2, 0) intersect y² = 4x at A and B in first quadrant such that harmonic mean (H) of AP & BP satisfies H > 8/√3 then slope of (m) lies always satisfies.

A

B

C

D
Question 6
4 / -1

A

B

C

D

Solution
Question 7
4 / -1

Let A be a point on the line and B(3, 2, 6) be a point in the space. Then the value of µ for which the vector is parallel to the plane is :

A
1/6

B
1/4

C
1/8

D
0

Solution
Question 8
4 / -1

Let ƒ : (–10, 10) → R be an even function. If n be the number of values of x for which then value of n is

A
2

B
3

C
4

D
9

Solution
Question 9
4 / -1

Let ,where ƒ(x) is a polynomial of degree less than equal to 2. If leading coefficient of polynomial is a, then the value of 2a + 1 is equal to:

A
2

B
3

C
5

D
7

Solution
Question 10
4 / -1

Suppose ƒ(1) = 3, ƒ'(1) = –6, h'(3) = 1. If g(x) = h(x²ƒ(x)) then value of g'(1) is :

A
0

B
2

C
3

D
5

Solution

g'(x) = h'(x²ƒ(x)) . [x²ƒ'(x) + 2xƒ(x)]

g'(1) = h'(ƒ(1)) . [ƒ'(1) + 2ƒ(1)] = 0