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Mathematics Test 216

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Mathematics Test 216
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Weekly Quiz Competition
  • Question 1
    4 / -1

    If the value of (1 + tan 1°)(1 + tan 2°)(1 + tan 3°)……….(1 + tan 44°)(1 +t an 45°) is 2λ, then the sum of the digits of the number λ is

    Solution

     

  • Question 2
    4 / -1

    If 2f(xy) = (f(x))+ (f(y))for all x, y ∈ R and f(1) = 3, then the value of  is equal to

    Solution

    From given functional equation, 2f(xy) = (f(x))+ (f(y))x, ∀ x, y ∈ R

    putting y = 1,

    2f(x) = f(x) + (f(1))xf(x) = 3x

     

  • Question 3
    4 / -1

    Solution

     

  • Question 4
    4 / -1

    If three positive real numbers a, b and c are in AP, with abc = 64, then minimum value of b, is

    Solution

    Since a, b, c are in A.P., therefore, b − a = d and c − b = d, where d is the common difference of the A.P.

    ∴ a = b − d & c = b + d

    Given, abc = 64

    ⇒ (b − d) b (b + d) = 64

    ⇒ b(b− d2) = 64

    But, b(b− d2) ≤ b × b(As d≥ 0 always)

    ⇒ b(b− d2) ≤ b3

    ⇒ b≥ 64

    ⇒ b ≥ 4

    Hence, the minimum value of b is 4.

     

  • Question 5
    4 / -1

    Consider a ΔABC with vertices at (0,−3)(−2√3, 3) and (2√3, 3), respectively. The incentre of the triangle with vertices at the mid-points of the sides of ΔABC is

    Solution

    Let A (0,−3), B (−2√3, 3) and (2√3, 3).

    Let, D, E & F are the mid-point of sides AB, BC and CA respectively.

    ∴ ΔDEF is an equilateral triangle.

    We know that in an equilateral triangle, the incentre, orthocentre, circumcentre and centroid coincide.

     

  • Question 6
    4 / -1

    If z is a non-real complex number, then the minimum value of  is (Where Im z = Imaginary part of z)

    Solution

    Let, z = r(cosθ + isinθ)

    z= r5(cos5θ + i sin5θ)

    Im(z5) = rsin5θ

    and (Im z)= rsin5θ

     

  • Question 7
    4 / -1

    If p always speaks against qq, then p → p ∨ ~q is,

    Solution

     

  • Question 8
    4 / -1

    A tower T1 of height 60 m is located exactly opposite to a tower T2 of height 80 m on a straight road. From the top of T1, if the angle of depression of the foot of T2 is twice the angle of elevation of the top of T2, then the width (in mm) of the road between the feet of the towers T1 and T2 is

    Solution

    Let, the width of the road the road is d.

    If the angle of the elevation is θ, then

    tan θ = 20/d, here 20 is the difference between the heights of T1 and T2.

    Given that, the angle of depression is twice of the angle of elevation.

    tan 2θ = 60/d

     

  • Question 9
    4 / -1

    The equation of the plane passing through the point (1,−3,−2) and perpendicular to planes x + 2y + 2z = 5 and 3x + 3y + 2z = 8, is

    Solution


     

  • Question 10
    4 / -1

    Let A = {(x, y) : y = ex, x ∈ R}, B = {(x, y) : y = e−x, x ∈ R}. Then

    Solution

    ∵ y = ex, y = e−x will meet, when e= e−x

    ⇒ e2x = 1,

    ∴ x = 0, y = 1

    ∴ A and B meet on (0, 1),

    ∴ A ∩ B ≠ ϕ.

     

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