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JEE Main Test 18

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JEE Main Test 18
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Weekly Quiz Competition
  • Question 1
    4 / -1

    Statement–1: Intensity of sound waves does not change when the listener moves towards or away from stationary source. 
    Statement–2: The motion of listener causes the apparent change in wavelength.

    Solution

    Intensity of sound at any point is energy flowing per second per unit area around that point. So, it will not change due to motion of listener. 
    The apparent wavelength changes with the motion of listener.

  • Question 2
    4 / -1

    A carnot engine takes 3 × 106 cal of heat from a reservoir at 627°C, and gives it to a sink at 27°C. The work done by the engine is

    Solution

    Work done by the engine while taking heat Q = 3 × 106 cal
    efficiency = 1-T1/T2 = W/Q1
    W/Q1 = 2/3
    W = 2 × 106 × 4.2 = 8.4 × 106 J. 
    Hence, option B is correct.

  • Question 3
    4 / -1

    Heating an aqueous solution of aluminium chloride to dryness will give

    Solution

    AI2CI6 6H2O → Al2O3 + 6HCI + 3H2O ­ 

    Hence, option C is correct.

  • Question 4
    4 / -1

    Consider separate solutions of 0.500 M C2H5OH (aq). 0.100 M Mg3(PO4)2(aq). 0.250 M KBr(aq) and 0.125 M Na3PO4(aq) at 25 °C. Which statement is true about these solutions, assuming all salts to be strong electrolytes?

    Solution

    For C2H5OH, π = 1 × 0.5 × RT 
    For KBr, π = 2 × 0.25 × RT 
    For Mg3(PO4)2, π = 5 × 0.1 × RT 
    For Na3PO4, π = 4 × 0.125 × RT 
    So, all are isotonic solutions. 
    Hence, option C is correct.

  • Question 5
    4 / -1

    Let A and B denote the statements 
    A: cos α + cosβ + cosγ = 0 
    B : sinα + sinβ + sinγ = 0 
    If cos(β – γ) + cos(γ – α) + cos(α – β) = – 3/2, then

    Solution

    cos(β–γ) + cos(γ – α) + cos(α – β) = –3/2 
    ⇒ 2cos (β – γ) + 2cos(γ– α) + 2cos(α – β) = –3 
    ⇒ Σ(cosβcosγ + 2Σsin α sinβ + 3 = 0 
    ⇒ (cosα+cosβ + cosγ)2 + (sinα + sinβ + sinγ)2=0 
    ⇒ cosα + cosβ + cosγ = 0 
    sinα + sinα + sinγ = 0 
    Hence, option C is correct.

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