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Kinetic Theory of Gases Test - 69

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Kinetic Theory of Gases Test - 69
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Weekly Quiz Competition
  • Question 1
    4 / -1
    Suppose ideal gas equation follows VP3 = constant. Initial temperature and volume of the gas are T and V respectively. If gas expands to 27V then its temperature will become
    Solution

  • Question 2
    4 / -1
    When the temperature of a gas is raised from 27°C to 90°C, the percentage increase in the r.m.s. velocity of the molecules will be
    Solution

  • Question 3
    4 / -1

    Solution

  • Question 4
    4 / -1
    Two spherical vessel of equal volume, are connected by a narrow tube. The apparatus contains an ideal gas at one atmosphere and 300K. Now if one vessel is immersed in a bath of constant temperature 600K and the other in a bath of constant temperature 300K. Then the common pressure will be

    Solution

  • Question 5
    4 / -1
    The r.m.s velocity of a gas at a certain temperature is √2 times than that of the oxygen molecules at that temperature. The gas can be
    Solution

  • Question 6
    4 / -1
    At what temperature, the mean kinetic energy of O2will be the same for H2 molecules at –73 °C
  • Question 7
    4 / -1
    The volume of a gas at pressure 21 × 104 N/m2 andtemperature 27°C is 83 litres. If R = 8.3 J/mol K, then the quantity of gas in g-mole will be
    Solution

  • Question 8
    4 / -1
    The pressure and temperature of an ideal gas in a closed vessel are 720 kPa and 40°C respectively. If 1/4thof the gas is released from the vessel and the temperature of the remaining gas is raised to 353°C, thefinal pressure of the gas is
    Solution

  • Question 9
    4 / -1
    An air bubble doubles its radius on raising from the bottom of water reservoir to be the surface of water in it. If the atmospheric pressure is equal to 10 m of water, the height of water in the reservoir is

    Solution

  • Question 10
    4 / -1
    It the r.m.s velocity of a gas at a given temperature (Kelvin scale) is 300 m/s. What will be the r.m.s velocity of a gas having twice the molecular weight and half the temperature on Kelvin scale =
    Solution

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