Current Electricity Test

Result

Current Electricity Test - 17

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Question 1
4 / -1

A galvanometer having internal resistence 10 Ω requires 0.01 A for a full scale deflection. To convert this galvanometer to a voltmeter of full scale deflection at 120 V, we need to connect a resistance of

A
11990 Ω in series

B
11990 Ω in parallel

C
12010 Ω in series

D
12010 Ω in parallel

Solution
Question 2
4 / -1

The neutral point on potentiometer's scale for two cells of emf 2.1 and E volt is observed at distances 40 cm and 56 cm respectively. The value of E is

A
2.10 V

B
2.94 V

C
1.50 V

D
1.20 V

Solution
Question 3
4 / -1

A voltmeter has resistance of G ohms and range V volt. The value of resistance used in series to convert it into a voltmeter of range n V volts is

A
nG

B
(n – 1)G

C

D

Solution
Question 4
4 / -1

The current in the primary circuit of a potentiometer is 0.2 A. The specific resistance and cross-section of the potentiometer wire are 4 × 10^-7 Ω-m and 8 × 10^-7 m² espectively. The potential gradient will be equal to

A
0.2 V/m

B
1 V/m

C
0.3 V/m

D
0.1 V/m

Solution
Question 5
4 / -1

A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter of range

A
1 A

B
1 mA

C
100 mA

D
10 mA

Solution
Question 6
4 / -1

The deflection in a moving coil galvanometer is reduced to half when it is shunted with a 40 Ω coil. The resistance of the galvanometer is

A
15Ω

B
20Ω

C
40Ω

D
80Ω

Solution
Question 7
4 / -1

In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2 Ω, the balancing length becomes 120 cm.The internal resistance of the cell is

A
4Ω

B
2Ω

C
1Ω

D
0.5Ω

Solution
Question 8
4 / -1

For measurement of potential difference, potentiometer is preferred in comparison to voltmeter because

A
potentiometer is more sensitive than voltmeter

B
the resistance of potentiometer is less than voltmeter

C
potentiometer is cheaper than voltmeter

D
potentiometer does not take current from the circuit
Question 9
4 / -1

The range of a voltmeter of resistance 500 Ω is 10 V. The resistance to be connected to convert it into an ammeter of range 10 A is

A
1 Ω in parallel

B
1 Ω in series

C
0.1 Ω in parallel

D
0.1 Ω in series

Solution
Question 10
4 / -1

Three voltmeters A, B and C having resistances R, 1.5 R and 3R respectively are used in a circuit as shown. When a potential difference is applied between X and Y, the readings of the voltmeters are V₁ , V₂ and V₃ respectively. Then,

A
V₁ = V₂ = V₃

B
V₁ < V₂ = V₃

C
V₁ > V₂ > V₃

D
V₁ > V₂ = V₃

Solution