Current Electri...

Five conductors are meeting at a point x as shown in the figure. What is the value of current in fifth conductor?

In the circuit shown, A and V are ideal ammeter and voltmeter respectively. Reading of the voltmeter will be

When a resistance of 2 ohm is connected across the terminals of a cell, the current is 0.5 ampere. When the resistance is increased to 5 ohm, the current is 0.25 ampere. The internal resistance of the cell is

A 5 V battery with internal resistance 2 Ω and a 2 V battery with internal resistance 1 Ω are connected toa 10 Ω resistor as shown in the figure

A primary cell has an e.m.f. of 1.5 volt, when short-circuited it gives a current of 3 ampere. The internal resistance of the cell is

A 50 V battery is connected across a 10 ohm resistor. The current is 4.5 ampere. The internal resistance ofthe battery is

The potential difference in open circuit for a cell is 2.2 volt. When a 4 ohm resistor is connected between its two electrodes the potential difference becomes 2 volt. The internal resistance of the cell will be

A new flashlight cell of e.m.f. 1.5 volt gives a current of 15 amp, when connected directly to an ammeter of resistance 0.04 52 . The internal resistance of cell is

A cell whose e.m.f. is 2 V and internal resistance is 0.1 Ω a, is connected with a resistance of 3.9 Ω. The voltage across the cell terminal will be

The reading of a high resistance voltmeter when a cell is connected across it is 2.2 V. When the terminals of the cell are also connected to a resistance of 5Ω the voltmeter reading drops to 1.8 V. Find the internalresistance of the cell