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Electrostatics Test - 56

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Electrostatics Test - 56
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  • Question 1
    4 / -1
    The potential energy of a charged parallel plate capacitor is U0, if a slab of dielectric constant k is inserted between the plates, then the new potential energy will be
    Solution

  • Question 2
    4 / -1
    The energy of a charged capacitor is given by the expression (q = charge on the conductor and C = its capacity)
    Solution

  • Question 3
    4 / -1
    In a charged capacitor, the energy resides
  • Question 4
    4 / -1
    If the circumference of a sphere is 2m, then capacitance of sphere in water would be
    Solution

  • Question 5
    4 / -1
    If the charge on a capacitor is increased by 2 coulomb, the energy stored in it increase by 21%. The original charge on the capacitor is
    Solution

  • Question 6
    4 / -1
    The potential gradient at which the dielectric of a condenser just gets punctured is called
  • Question 7
    4 / -1
    A parallel plate condenser has a capacitance 50µF in air and 110µF when immersed in an oil. The dielectric constant \'k\' of the oil is
    Solution

  • Question 8
    4 / -1
    The potential to which a conductor is raised, depends on
  • Question 9
    4 / -1
    A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between its plates is ‘d’. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant k1 = 3 and thickness d/3 while the other one has dielectric constant k2 = 6 and thickness 2d/3. Capacitance of the capacitor is now
    Solution

  • Question 10
    4 / -1
    1000 small water drops each of radius r and charge q coalesce together to form one spherical drop. The potential of the big drop is larger than that of the smaller drop by a factor of
    Solution

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