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Electrostatics Test - 72

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Electrostatics Test - 72
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Weekly Quiz Competition
  • Question 1
    4 / -1
    Two equal negative charge –q are fixed at the fixed points (0, a) and (0, –a) on the Y-axis. A positive charge Q is released from rest at the point (2a, 0) on the X-axis. The charge Q will
    Solution

  • Question 2
    4 / -1
    An electric line of force in the xy-plane is given by equation x2 + y2 =1. A particle with unit positive charge, initially at rest at the point x = 1, y = 0 in the xy-plane
    Solution

  • Question 3
    4 / -1
    A positively charged ball hangs from a silk thread. We put a positive test charge q0 at a point and measure F/q0, then it can be predicted that the electric field strength E
    Solution

  • Question 4
    4 / -1
    A solid metallic sphere has a charge +3Q. Concentric with this sphere is a conducting spherical shell having charge –Q. The radius of the sphere is a and that of the spherical shell is b(b > a). What is the electric field at a distance R(a < R < b) from the centre
    Solution

  • Question 5
    4 / -1
    Two equal charges q of opposite sign separated by a distance 2a constitute an electric dipole of dipole moment p. If P is a point at a distance r from the centre of the dipole and the line joining the centre of the dipole to this point makes an angel θ with the axis of the dipole, then the potential at P is given by (r >> 2a) (where p = 2aq)
    Solution

  • Question 6
    4 / -1
    A point charge q is placed at a distance a/2 directly above the centre a square of side a. The electric flux through the square is
    Solution

  • Question 7
    4 / -1
    Two identical thin rings each of radius R meters are coaxially placed at a distance R meters apart. If Q1 coulomb and Q2 coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a charge q from the centre of one ring to that of other is
    Solution

  • Question 8
    4 / -1

    Solution

  • Question 9
    4 / -1
    A charge +q is fixed at each of the points x = x0, x = 3x0, x = 5x0.... infinite, on the x-axis and a charge –q is fixed at each of the points x = 2x0, x = 4x0, x = 6x0, .... infinite. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q / (4πɛ0r). Then, the potential at the origin due to the above system of charges is
    Solution

  • Question 10
    4 / -1
    Let C be the capacitance of a capacitor discharging through a resistor R. Suppose t1 is the time taken for the energy stored in the capacitor to reduce to half its initial value and t2 is the time taken for the charge to reduce to one-fourth its initial value. Then, the ratio t1 / t2 will be
    Solution

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