Electromagnetic Induction Test

Result

Electromagnetic Induction Test - 24

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Weekly Quiz Competition

Question 1
4 / -1

A square loop of side 10 cm and resistance 2Ω is moved with velocity v_o as shown in fig. The uniform magnetic field is 3T with what speed should the loop be moved so that a steady current of 1.5 mA flows in the loop.

A
1 cms^–1

B
2 cms^–1

C
3 cms^–1

D
4 cms^–1

Solution
Question 2
4 / -1

The time constant of a LR circuit is 20 ms The circuit is connected at t = 0 and the steady state current is found to be 4A. Find the current at 80 ms.

A
0.98 A

B
1 A

C
0.44 A

D
0.88 A

Solution
Question 3
4 / -1

A metal rod of length 2 m rotates vertically about one of its end with frequency 2 Hz. The horizontal component of earth's magnetic field is 3.14 × 10^–5 T then emf developed between two ends of road is.....

A

B

C

D
Question 4
4 / -1

Pure inductance of 3H each are connected as shown below. The equivalent inductance of the circuit is

A
1 H

B
2 H

C
3 H

D
9 H
Question 5
4 / -1

A coil of inductance 300 mH and resistance 2Ω is connected to a source of voltage 2V. The current reaches half of its steady state value in.........

A
0.15 sec

B
0.3 sec

C
0.05 sec

D
0.1sec
Question 6
4 / -1

The rms value of an ac of 50 Hz is 10 amp.The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be,

A

B

C

D
Question 7
4 / -1

An alternating current is given by the equation I = I₁coswt + I₂ sinwt. The rms current is given by,

A

B

C

D
Question 8
4 / -1

A
20 watts

B
40 watts

C
1000 watts

D
0 watts
Question 9
4 / -1

In ac circuit with voltage V and current I, the power dissipated is.

A

B

C

D
Depends on the phase between V and I
Question 10
4 / -1

A lamp consumes only 50% of peak power in an ac circuit. What is the phase difference between the applied voltage and the circuit current.

A

B

C

D

Solution