Electromagnetic Induction Test

Result

Electromagnetic Induction Test - 6

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Question 1
1 / -0

In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates with frequency ω in a magnetic field B. The maximum value of emf generated in the coil is

A
N.A.B.ω

B
N.A.B.R.ω

C
N.A.B

D
N.A.B.R

Solution

E_ind(max) = NABω
Question 2
1 / -0

The core of any transformer is laminated so as to

A
reduce the energy loss due to eddy currents

B
make it light weight

C
make it robust and strong

D
increase the secondary voltage.

Solution

The core of any transformer is laminated so as to reduce the energy loss due to eddy currents.
Hence, option A is correct.
Question 3
1 / -0

A coil is suspended in a uniform magnetic field, with the plane of the coil parallel to the magnetic lines of force. When a current is passed through the coil it starts oscillating; it is very difficult to stop. But if an aluminium plate is placed near to the coil, is stops. This is due to

A
development of air current when the plate is placed

B
induction of electrical charge on the plate

C
shielding of magnetic lines of force as aluminium is a paramagnetic material

D
electromagnetic induction in the aluminium plate giving rise to electromagnetic damping

Solution

Oscillating coil produces time variable magnetic field. If cause eddy current in the aluminium plate which causes anti-torque on the coil, due to which is stops.
Hence, option D is correct.
Question 4
1 / -0

Two coaxial solenoids are made by winding thin insulted wire over a pipe of cross-sectional area A = 10 cm² and length = 20 cm. If one of the solenoids has 300 turns and the other 400 turns, their mutual inductance is
(μ₀ = 4π × 10^-7 T mA^-1)

A
4.8 π × 10^-5 H

B
2.4 π × 10^-4 H

C
2.4 π × 10^-5 H

D
4.8 π × 10^-4 H.

Solution

The mutual inductance= AN₁N₂μ₀/l

= 10*300*400*4π × 10^-7/20*100

=600*4π × 10^-7

=2.4π × 10^-4 H