Moving Charges ...

A proton of mass m and charge +e is moving in a circular orbit in a magnetic field with energy 1 MeV. What should be the energy of α–particle (mass = 4m and charge = +2e), so that it can revolve in the path of same radius

A proton and an α–particle enter a uniform magnetic field perpendicularly with the same speed. If proton takes 25 μ sec to make 5 revolutions, then the periodic time for the α–particle would be

A proton (mass = 1.67 × 10^–27kg and charge = 1.6 × 10^–19 C) enters perpendicular to a magnetic field of intensity 2 weber/m² with a velocity 3.4 × 10⁷m/sec. The acceleration of the proton should be

A charged particle is moving in a circular orbit of radius 6 cm with a uniform speed of 3 × 10⁶ m/s under the action of a uniform magnetic field 2 × 10^–4 wb/m² at right angles to the plane of the orbit. The charge to mass ratio of the particle is

A uniform magnetic field acts at right angles to the direction of motion of electrons. As a result, the electron moves in a circular path of radius 2 cm. If the speed of the electrons is doubled, then the radius of the circular path will be

A current I flowing through the loop as shown in figure. The magnetic field at centre O is