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Oscillations Test - 8

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Oscillations Test - 8
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  • Question 1
    4 / -1

    Solution

  • Question 2
    4 / -1
    A small block is connected to one end of a massless spring of unstretched length 4.9 m. The other end of the spring (see the figure) is fixed. The system lies on a horizontal frictionless surface. The block is stretched by 0.2 m and released from rest at t = O. Then, it executes simple harmonic motion with angular frequency ω=π⁄3 rad /s. Simultaneously at t = 0, a small pebble is projected with speed v from point P at an angle of 45° as shown in the figure. Point P is at a horizontal distance of 10 m from point 0. If the pebble hits the block at t = 1 s, the value of v is (take, g = 10 m/s2)

    Solution

  • Question 3
    4 / -1
    For a body performing SHM, at a distance A ⁄ √2, then correct relation between KE and PE will be
    Solution

  • Question 4
    4 / -1
    The x-t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at

    Solution

  • Question 5
    4 / -1
    A particle of mass m is executing oscillations about the origin on the X-axis with amplitude A. Its potential energy U(x) = ax4, where a is positive constant. The x-coordinate of mass where potential energy is one-third of the kinetic energy of particle is
    Solution

  • Question 6
    4 / -1
    A particle starts oscillating simple harmonically from its equilibrium position with time period T. The ratio of ICE and PE of other particle at t = T/12 is
    Solution

  • Question 7
    4 / -1
    The average acceleration of a particle performing SHM over one complete oscillation is
  • Question 8
    4 / -1
    U is the PE of an oscillating particle and F is the force acting on it at a given instant. Which of the following is correct?
    Solution

  • Question 9
    4 / -1

    Solution

  • Question 10
    4 / -1
    A particle of amplitude A is executing simple harmonic motion. When the potential energy of particle is half of its maximum potential energy, then displacement from its equilibrium position is
    Solution

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