Dual Nature of ...

The energy of a photon is equal to the kinetic energy of proton.The energy of a photon is E. Let λ₁ be the de- Brogile wavelength of the proton and λ₂ be the wavelength of the photon. The ratio λ₁/λ₂ is proportional to

An electron and a proton are accelerated through the same potential difference. The ratio of their de – Broglie wavelength will be

If the kinetic energy of a free electron doubles, its de Broglie wavelength changes by the factor

An element with atomic number Z=11 emits k_α X – ray of wavelength λ . The atomic number of element which emits K_α X – ray of wavelength 4λ.

A small metal plate (work function = 1.17 eV) is placed at a distance of 2 m from a monochromatic light source of wavelength 4.8 × 10⁻⁷ m and power 20 watt. The light falls normally on the plate. The number of photons striking the metal plate per second per sq metre area will be

The minimum light intensity that can be perceived by the eye is about 10^-10 w/m². The number of photons of wavelength 5.6 × 10^–7 m that must enter the pupil of area 10^–4 m² per second, for vision is approximately equal to (h = 6.6 × 10^-34 Js)

The earth receives 8.4 J/minute/m² energy from the sun. If the solar energy in 10 × 10⁴ m² area is concentrated in a cup filled with 100 g water at 0^oC, in how much time the water will boil

A photon and electron have same de – Broglie wavelength. Given that υ is the speed of electron and c is the velocity of light. E_e, E_p are the kinetic energy of electron and photon respectively. p_e, p_h are the momentum of electron and photon respectively. Then which of the following relation is correct.

When electric bulb having 100 W efficiency emits photon having wavelength 410 mm every second, numbers of photons will be......(h = 6 × 10^–34 J.s, c = 3 × 10⁸ ms^–1 )

Photocell cell is enlightened by small bright source 1 m away. If the same light source is placed 1/2 m away, number of electrons emitted by cathode will be............