Dual Nature of Radiation and Matter Test

Result

Dual Nature of Radiation and Matter Test - 65

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Weekly Quiz Competition

Question 1
4 / -1

The variation of wavelength λ of the K_α, line with atomic number Z of the target is shown by the following curve of

A
A

B
B

C
C

D
None of these

Solution
Question 2
4 / -1

In the graph given below. If the slope is 4.12 × 10^–15 Vs, then value of \'h\' should be

A
6.6 × 10^–31 J-s

B
6.6 × 10^–34 J-s

C
9.1 × 10^–31 J-s

D
None of the above

Solution
Question 3
4 / -1

The curves (a), (b), (c) and (d) show the variation between the applied potential difference (V) and the photoelectric current (i), at two different intensities of light (I₁ > I₂). In which figure is the correct variation shown

A

B

C

D

Solution
Question 4
4 / -1

The figure showing the correct relationship between the stopping potential V₀ and the frequency v of light for potassium and tungsten is

A

B

C

D

Solution
Question 5
4 / -1

The log-log graph between the energy E of an electron and its de-Broglie wavelength X will be

A

B

C

D

Solution
Question 6
4 / -1

The graph between the square root of the frequency of a specific line of characteristic spectrum of X-rays and the atomic number of the target will be

A

B

C

D

Solution
Question 7
4 / -1

In the diagram a graph between the intensity of X-rays emitted by a molybdenum target and the wavelength is shown, when electrons of 30 keV are incident on the target. In the graph one peak is of K_α line and the other peak is of K_β line

A
First peak is of K_α line at 0.6 Å

B
Highest peak is of K_α line at 0.7 Å

C
If the energy of incident particles is increased, then the peaks will shift towards left

D
If the energy of incident particles is increased, then the peaks will shift towards right

Solution
Question 8
4 / -1

The maximum value of stopping potential in the following diagram is

A
–4 V

B
–1 V

C
–3 V

D
–2 V

Solution
Question 9
4 / -1

In a parabola spectrograph, the velocities positive ions P, Q, R and S are v₁, v₂, v₃ and v₄respectively. Then

A
v₁ > v₂ > v₃ > v₄

B
v₁ < v₂ < v₃ < v₄

C
v₁ = v₂ = v₃ = v₄

D
v₁ << v₂ > v₃ < v₄

Solution
Question 10
4 / -1

In Thomson spectrograph experiment, four positive ions P, Q, R and S are situated on YX curve as shown in the figure

A
The specific charge of R and S are same

B
The masses of P and S are same

C
The specific charges of Q and R are same

D
The velocities of R and S are same