Self Studies

Physics Test-30

Result Self Studies

Physics Test-30
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

    Which of the following statement is correct?

    Solution

    The amplitude of torque is as follows,

    \(\Rightarrow[T]=\left[M^{1} L^{2} T^{-2}\right]\)

    The dimension of the work is as follows,

    \(\Rightarrow[T]=\left[M^{1} L^{2} T^{-2}\right]\)

    The amplitude of the momentum is as follows,

    \(\Rightarrow[\mathrm{T}]=\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-1}\right]\)

    From the above explanation, it is clear that torque and work have same dimension but momentum has a different dimension.

  • Question 2
    4 / -1

    Which of the following statement is incorrect regarding center of mass?

    Solution
    The Center of Mass of a body will always be inside or outside of the body, it depends upon size, mass and shape of the body.
  • Question 3
    4 / -1

    Which of the following laws was expressed by Nernst?

    Solution

    The third law was developed by Walther Nernst during the years \(1906–12\), and is therefore often referred to as Nernst's theorem or Nernst's postulate. The third law of thermodynamics states that the entropy of a system at absolute zero is a well-defined constant. This is because a system at zero temperature exists in its ground state, so that its entropy is determined only by the degeneracy of the ground state.

    In \(1912\) Nernst stated the law thus: "It is impossible for any procedure to lead to the isotherm \(T = 0\) in a finite number of steps."

  • Question 4
    4 / -1

    An electric bulb of \(60 \mathrm{~W}\) is used for \(6 \mathrm{~h}\) per day. Calculate the 'units' of energy consumed in one day by the bulb.

    Solution

    Power of electric bulb \(=60 \mathrm{~W}\)\(=0.06 \mathrm{~kW}\)

    Time used, \(t=6 \mathrm{~h}\)

    Energy \(=\) power \(\times\) time taken

    \(=0.06 \mathrm{~kW} \times 6 \mathrm{~h}\)

    \(=0.36 \mathrm{~kW} \mathrm{~h}\)

    \(=0.36\) units.

    The energy consumed by the bulb is \(0.36\) units.

    Hence, the correct option is (A).

  • Question 5
    4 / -1

    Two spherical bodies of mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centers equal to 12R. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is:

    Solution

    Let the spheres collide after time t, when the smaller sphere covered distance \(x_{1}\) and bigger sphere covered distance \(x_{2}\).

    The gravitational force acting between two spheres depends on the distance which is a variable quantity.

    Just before the collision, total distance travelled by both \(=9 R\)

    If \(x\) is the distance travelled by the block of mass \(M\) and \(9 R-x\) the distance travelled by block of mass \(5 \mathrm{M}\).

    As the centre of mass of system, not change, then:

    \(M x=5 M(9 R-x)\) \(x=7.5 R\)

  • Question 6
    4 / -1

    The velocity at which the laminar flow stops is known as:

    Solution
    The velocity at which the laminar flow stops is known as lower critical velocity. In this, the flow enters from laminar to transition period which exists between the laminar and turbulent flow.
  • Question 7
    4 / -1

    Find the electric charge \(Q_{1}\) on plates of capacitor \(C_{1}\), shown in Figure below:

    Solution

    Let,

    Effective capacitance \(= C\)

    Then:

    \(\frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}\)

    \(=\frac{1}{8}+\frac{1}{16}+\frac{1}{24}\)

    \(=\frac{6+3+2}{48}\)

    \(C=\frac{48}{11} \mu F\)

    Potential difference, \(V=110 V\)

    We know that:

    Charge, \(Q=C V\)

    \(Q=\frac{48}{11} \times 10^{-6} \times 110\)

    \(=480 \times 10^{-6}\)

    \(=48 \times 10^{-5}\)

    Since the capacitors are in series each capacitor has the same charge i.e., \(48 \times 10^{-5} C\).

  • Question 8
    4 / -1

    Which of the following does not conduct electricity?

    Solution

    Sugar solutiondoes not conduct electricity.

    When sugar is dissolved in water, sugar does not dissociate into ions. Thus, a sugar solution contains only neutral molecules of sugar and water. The neutral molecules do not have any charge and thus, do not conduct electricity. Thus, the sugar solution is a bad conductor of electricity.

  • Question 9
    4 / -1

    Which one of the following statements is incorrect about electromagnetic waves?

    Solution

    Electromagnetic waves or EM waves:

    • Electromagnetic waves or EM waves are waves that are formed as a result of vibrations between an electric field and a magnetic field and they are perpendicular to each other and to the direction of the wave.
    • An accelerating charged particle produces an electromagnetic (EM) wave.
    • A charged particle oscillating about an equilibrium position is an accelerating charged particle.

    As we know that EM waves do not have any charge, thus they are not deflected by an electric field and magnetic field. So, option (A) is incorrect.

    Electromagnetic waves do not require any matter to propagate from one place to another as it consists of photons. They can move in a vacuum. Thus, option (B) is correct.

    Electromagnetic waves or EM waves are waves that are formed as a result of vibrations between an electric field and a magnetic field and they are perpendicular to each other and to the direction of the wave. Thus, option (C) is correct.

    The electromagnetic wave moves with the speed of light. Thus, option (D) is correct.

  • Question 10
    4 / -1

    In an unbiased p – n junction, holes diffuse to n – region from p – region because :

    Solution

    The usual tendency of the charge carriers is to disperse towards the lower concentration region from the higher concentration region. So it can be said that in an unbiased p-n junction, holes disperse from p-region to the n-region as the p-region has a greater concentration of holes than in n-region.

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now