Physics Test-9

When a particle moves along a straight path, then the particle has tangential acceleration only

The acceleration of a particle at any instant moving along a circular path in a direction tangential to that instant, is known as the tangential component of acceleration or tangential acceleration.

Let intensity from the smaller slit be I so, the intensity from the bigger slit will be \(4 I\) since it is 4 times of smaller slit.

Now, \(I _{\max }=4 I + I +2 \sqrt{ I (4 I )}\)

\(=5 I +2 \sqrt{4 I ^2} \)

\(=5 I +2(2 I ) \)

\(=9 I\)

\(I_{min} =4 I + I -2 \sqrt{ I (4 I )}\)

\(=5 I -2(2 I )\)

\(= I\)

So, \(\frac{I_{\max }}{I_{\min }}=\frac{9 I}{I}=\frac{9}{1}=9:1\)

Given,

The mass of the body, \(m=4\) kg

Final velocity, \(v = 25\) m/s

Initial velocity, \(u = 15\) m/s

Time, \(t = 5\) s

From the first equation of motion,

\(25=15+a \times 5\)

\(10=a \times 5\)

\(a=2\)

From the Newton's second law,

\(F=ma\)

\(=4 \times 2\)

\(=8\)N

The \(P-V\) diagram of adiabatic process, isothermal process and isobaric process. 

Work done in process= area enclosed by \(P-V\) diagram with volume axis.Since area under the curve is maximum for adiabatic process, so work done on the gas will be maximum for adiabatic process.

Here simple pendulum is at a certain height and at extreme position it will not have any velocity.

So, kinetic energy will be zero. Whereas \(U=m \times g \times h\).

As it is at certain height it has some value for h. Therefore, it will have certain potential energy.

Let the intensities be \(x\) and \(y\) ratio is \(9: 1\) let it be \(9 k\) and \(k\) maximum intensity is \((\sqrt{x}+\sqrt{y})^2=9 k\) minimum intensity is \((\sqrt{x}-\sqrt{y})^2= k\).

\(\frac{\sqrt{x}+\sqrt{y}}{\sqrt{x}-\sqrt{y}}=\frac{9}{1} \)

\(\frac{x}{y}=\frac{4}{1}\)

The energy density of the electromagnetic wave in terms of magnetic field is given by:

\(U=\frac{1 B_0^2}{2 \mu_0} \)

\(\Rightarrow B_0=\sqrt{2 \times \mu_0 \times U}\)

From electromagnetic theory,

\(\mu_0=\frac{1}{c^2 \varepsilon_0} \)

\(=\frac{4 \pi \times 9 \times 10^9}{\left(3 \times 10^8\right)^2}=4 \pi \times 10^{-7} \)

\(\therefore B_0=\sqrt{2 \times 4 \pi \times 10^{-7} \times 1.02 \times 10^{-8}} \)

\(B_0=160 \times 10^{-9} \mathrm{~T} \)

\(B_0=160 \mathrm{nT}\)

In the third law of motion, action and reaction are equal, opposite and act on two different bodies.

Newton's Third Law of Motion states that 'To every action, there is an equal and opposite reaction'.

Newton's third law of motion is applicable irrespective of the nature of the forces. The forces of action and reactions may be mechanical, gravitational, electric, or of any other nature.

Sensible heat is the heat required toIncrease the temperature of a liquid or vapour.

Sensible heat is the energy required to change the temperature of a substance with no phase change. The temperature change can come from the absorption of sunlight by the soil or the air itself.

Positive Beilstein shows that halogens may be present. A positive Beilstein’s test for halogens does not always indicate the presence of halogen since some halogen-free compounds viz. urea, thiourea, amides etc. also respond this test. The reason being the fact that these halogen-free compounds form cuprous cyanide which is volatile and decomposes to copper which burns with green flame.