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  • Question 1
    4 / -1

    Two horses P and Q are running at a certain point at the speed of 15 km/hr and 17 km/hr respectively. What is the distance between them after 5 hrs if they running in the opposite directions?

    Solution

    Given:

    Two horses P and Q are running at a certain point at the speed of 15 km/hr and 17 km/hr respectively.

    If the speed of the two trains is x km/hr and y km/hr respectively if x > y.

    Relative speed, if opposite directions = (x + y) km / hr

    Speed =DistanceTime

    Relative speed of both horses = 17 + 15 = 32 km/hr

    Distance between them after 5 hrs = 32 × 5 = 160 km

  • Question 2
    4 / -1

    If a boat walks smoothly along the streamline, the distance of 36 km is completed in 3 hours. While returning, it completes the same distance in 9 hours. So what is the speed of the boat?

    Solution

    Let the speed of the boat be c and the speed of the current is v.

    So we have,

    Speed of the boat with the stream =c+v=363=12km/hr

    Speed of the boat against the stream =c-v=369=4km/hr

    By adding the above result obtained and removing v, we get,

    2c=16km/hr

    c=8km/hr

  • Question 3
    4 / -1

    A train 'B' speeding with 100 km/hr crosses another train C, running in the same direction, in 2 minutes. If the length of train B and C be 150 m and 250 m respectively, what is the speed of train C (in km/hr)?

    Solution

    Given:

    Speed of train B = 100 km/hr

    Let speed of train C be x km/hr,

    Length of train B and C are 150 m and 250 m respectively.

    As we know,

    Speed=DistanceTime

    ⇒ (100 - x) ×518 = 150+2502×60

    ⇒ (100 - x)=400120×185

    ⇒ 100 - x = 12

    ⇒ x = 100 - 12

    ⇒ x = 88

    Speed of the train C is 88 km/hr.

  • Question 4
    4 / -1

    If (x – 4) and (x + 6) are the factors of equation x2 + ax + b = 0 then find the value of (a – b)?

    Solution

    Given:

    (x – 4) and (x + 6) are the factors of equation x2 + ax + b = 0

    If (x – p) is the factors equation x2 + ax + b = 0 then ‘p’ will be the root of the equation.

    Roots of equation x2 + ax + b = 0 will be: 4 and -6.

    Putting the values of the roots we will get two equations as follows:

    16 + 4a + b = 0

    ⇒ 4a + b = -16 ---- (1)

    And

    36 – 6a + b = 0

    ⇒ -6a + b = - 36 ---- (2)

    Solving these two equations we get

    ⇒ a = 2 and b = -24

    So,

    (a – b) = 2 – (-24) = 26

  • Question 5
    4 / -1

    Simplify:

    \(1.45 \div 2.9 \times 4.11+1.002-.005+.98\)

    Solution

    Solving, using BODMAS rule,

    \(=\left(\frac{1.45}{2.9}\right) \times(4.11)+1.002-.005+.98\)

    \(=(0.5) \times(4.11)+1.002-.005+.98\)\(=2.055+1.002-.005+.98\)\(=4.032\)

  • Question 6
    4 / -1

    The average price of 20 books is Rs. 14, while the average price of 18 of these books is Rs. 13. Out of the remaining two books, if the value of one book is 21.05% of the other, what will be the value of each of these two books?

    Solution

    Let the price of remaining 2 books be x and y.x = 21.05%y⇒ x = 0.2105y

    ⇒ Total price of 20 books = Rs. 14 × 20 = Rs. 280

    ⇒ Total price of 18 books = Rs. 13 × 18 = Rs. 234

    Total price = Price of 18 books + Price of 2 books⇒ 280 = 234 + x + y⇒ 46=(1+0.2105)yy = 38

    ⇒ x = 0.2105y ⇒ x = 8

  • Question 7
    4 / -1

    Which of the following is not the additive inverse of a?

    Solution

    The additive inverse of a is ( -a).

    The additive inverse of an integer is the same integer value with opposite sign.

  • Question 8
    4 / -1

    A 460 litre of the mixture contains milk and water in the ratio 11 ∶ 12. How much milk must be added to the mixture so that it contains milk and water in the proportion of 3 ∶ 2. (In liters)

    Solution

    Milk content in mixture\(=\frac{11}{23} \times 460=220\)litres

    Water content\(=460-220=240\)litres

    Now, Milk content after addition= \(240 \times \frac{3}{2}=360\)litres

    Milk added\(=360-220=140\)litres

  • Question 9
    4 / -1

    The probability of getting a number on a roll of one die having total of 6 outcomes is p. A pair of die is rolled. The mean is equal to 0.5. Find the probability of not getting number 5 on at most one die on roll of the pair of dice. 

    Solution

    \(\Rightarrow \mathrm{n} \times \mathrm{p}=0.5\)    {Mean = n × probability of each outcome}

    \(\Rightarrow 6 \mathrm{p}=0.5\)

    \(\Rightarrow \mathrm{p}=\frac{1}{12}\)

    Probability of not getting number 5 on at most one die \(=1-\mathrm{p}\) (Getting number 5 on both dice) \(=1-(\frac{1}{12} \times \frac{1}{12})\) \(=\frac{143}{144}\)

  • Question 10
    4 / -1

    Which of the following condition is TRUE about the similarity of triangle ABC and DEF given below?

    Solution

    If \(\angle A=\angle D\), then
    \(\Rightarrow \frac{A B}{A C}=\frac{D E}{D F}\)
    \(\Rightarrow \frac{14}{10}=\frac{7}{5} \)
    \(\Rightarrow \frac{7}{5}=\frac{7}{5}\)

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