General Test - 34

Given:

Akash and Babul started a business by investing their amount in the ratio of 2 : 3

Concept Used:

In partnership, business profit is distributed as their investment ratio

Let, the investment of Akash and Babul are 2x and 3x

According to the question,

⇒ 3x = 2400

⇒ x = 800

∴ The profit amount get by Akash is 2x = 2 × 800

⇒ Rs. 1600

∴ The profit amount get by Akash at the end of the year is Rs. 1600

Given,

Principal, P \(=\) Rs. \(16,500\)

Time, T \(=4\) years

Rate, R \(=16\%\)

Simple Interest \(=\frac{P \times T \times R}{100}\)

\(=\frac{16500 \times 4 \times 16}{100}\)

\(=\) Rs. \(10,560\)

Let C. P. of the bag = \(100 x \Rightarrow\) S.P. = \(140\% \) of C.P. = \(140x\), then profit = S.P. - C.P. = \(140x - 100x\) = \(40x\)

Now, according to the question, profit = ₹ 880 \(\Rightarrow 40x = 880\)

\(\Rightarrow x = \frac{880}{40}=\) ₹ 22

Then C.P. of bag = \(100 \times 22=\) ₹ 2200

Fruit vendor bought bananas at the rate of \(10\) bananas for₹\(8\) and sold them at the rate of \(8\) bananas for₹\(10\)

Number of bananas bought \(=\) LCM of \((10\) and \(8)=40\)

C.P \(=(\frac{8 }{ 10}) \times 40=\)₹\( 32 \)

S.P \(=(\frac{10 }{ 8}) \times 40=\)₹\( 50\) So,Profit \(=50-32=\)₹\(18\)

Profit percent \(=(\frac{18 }{ 32}) \times 100=56.25 \%\)

X% of Y = Y% of X

Suppose the maximum marks are ‘M’ and passing marks are ‘P’. So,

28% of M = P - 40        ---(i) And

40% of M = P + 32        ---(ii)

From both the equations: ⇒ M = 600 and P = 208

∴ Maximum marks of the examination = 600

Given:\((\frac{1 }{ 5})^{3 y}=0.008\)

\((\frac{1 }{ 5})^{3 y}=(0.2)^{3 y} \)

\(\Rightarrow\left(0.2^3\right)^y=0.008 \)

\(\Rightarrow\left(0.2^3\right)^y=\left(0.2^3\right)^1\)

On comparing, \(y=1\)

\((0.25)^y=0.25^1=0.25\)

Given:\(25+12 \times 33-25 \div 5\)

\(= 25+12 \times 33-5\)\(=416\)