General Test - 41

Given,

Simple interest, SI \(=\) Rs. \(4819.50\)

Time, \(t = 6\) year

Let, the principle \(={P}\)

Therefore,

Rate, \(r = 9\) per annum

We know that,

Simple Interest \(=\frac{\text { Principal } \times \text { Time } \times \text { Rate }}{100}\)

\(\therefore 4819.50=\frac{P \times r \times t}{100}\)

\(\Rightarrow 481950=P \times 9 \times 6\)

\(\Rightarrow P=\) Rs. \( 8925\)

Let the cost price be x.

He got 25% discount =(100 - 25)% =75%

So, he paid 0.75x.

Given no discount then he would have paid 185 more.

So,$\frac{x}{4}=185$ ⇒ x = 740

So Ramu paid 740-185⇒ Rs. 555

Let, ' \(x\) ' be the maximum marks.

Nilesh scores \(188\) marks and he fails by \(22\) marks. This means Nlilesh requires \(22\) more marks to pass an exam \(= 188+22\) \(= 210\)

Nilesh has to score at least \(35\%\) of maximum marks to pass an exam. \(\Rightarrow 35 \%\) of \(x=210\) \(\Rightarrow x=600\)

Therefore, the maximum marks of an examination is 600.

Income = Expenditure + Saving

Ratio of income : expenditure : savings⇒ 100 : 80 : 20 or 5 : 4 : 1

Now let 5x, 4x and x be the income, expenditure and savings.

New income = 5x + 5x × 30% = 6.5x

New expenditure = 4x + 4x × 25% = 5x

New savings = 6.5x – 5x = 1.5x

% change in savings \(\frac{(1.5x – x)}{x}\) × 100 = +50%

Given:

C,D and E together fill a tank in 20 minutes.

Pipe C alone can fill it in 45 minutes

Pipe D alone can fill it in 60 minutes

Tank filled in 1 minute by C, D and E \(= \frac{1}{20}\)

Tank filled by C in 1 minute \(= \frac{1}{45}\);

Tank filled by D in 1 minute \(= \frac{1}{60}\)

Time taken by pipe E alone to fill a tank \(=\left[(\frac{1}{20})-(\frac{1}{45}+\frac{1}{60})\right]\)

\(=[(\frac{1}{20})-(\frac{7}{180})]\)

\(=[\frac{(9-7)}{180}]\)

\(=\frac{2}{180}\)

= 90 minutes

Given:\(\frac{3}{8} \div\left(\frac{5}{3}-\frac{1}{6}\right)+\frac{5}{8} \)

\(=\frac{3}{8} \div\left(\frac{10-1}{6}\right)+\frac{5}{8} \)

\(=\frac{3}{2 \times 4} \times \frac{2 \times 3}{9}+\frac{5}{8} \)\(=\frac{7}{8}\)