General Test

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General Test - 7

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Weekly Quiz Competition

Question 1
4 / -1

Directions For Questions

Direction: Study the following pie chart carefully & answer the question given below it.

The pie chart given below shows the break-up of the cost of construction of a house (in degrees). Assuming that the total cost of construction is Rs. \(60000\), answer the question given below.

...view full instructions

The amount spent on cement is:

A
Rs. \(20000\)

B
Rs. \(16000\)

C
Rs. \(12000\)

D
Rs. \(10000\)

Solution

Given,

Total cost = Rs. \(60000\)

The break-up of the cost of construction of a house (in degrees) for cement \(=72\)

Amount spent on cement \(=\frac{72}{360} \times 60000\)

\(=\frac{4320000}{360}\)

\(=\) Rs. \(12000\)
Question 2
4 / -1

Directions For Questions

Direction: Study the following pie chart carefully & answer the question given below it.

The pie chart given below shows the break-up of the cost of construction of a house (in degrees). Assuming that the total cost of construction is Rs. \(60000\), answer the question given below.

...view full instructions

The amount spent on labour exceeds the amount spent on steel by:

A
\(5 \%\) of the total cost

B
\(10 \%\) of the total cost

C
\(12 \%\) of the total cost

D
\(15 \%\) of the total cost

Solution

Given,

Total cost \(=\) Rs. \(60000\)

Amount spent on labour \(=\frac{90}{360} \times 60000\)

\(=\) Rs. \(15000\)

Amount spent on steel \(=\frac{54}{360} \times 60000\)

\(=\) Rs. \(9000\)

Difference \(=15000-9000\)

\(=\) Rs. \(6000\)

Let the amount spent on labour exceed the amount spent on steel by \(x \%\) of the total cost.

Then,

\(\frac{x \times 60000}{100}=6000\)

\(\Rightarrow x \times 600=6000\)

\(\Rightarrow x=\frac{6000}{600}\)

\(\Rightarrow x=10\)

The amount spent on labour exceeds the amount spent on steel by \(10 \%\) of the total cost.
Question 3
4 / -1

Directions For Questions

Direction: Study the following pie chart carefully & answer the question given below it.

The pie chart given below shows the break-up of the cost of construction of a house (in degrees). Assuming that the total cost of construction is Rs. \(60000\), answer the question given below.

...view full instructions

The amount spent on cement, steel and supervision is what percent of the total cost of construction?

A
\(40 \%\)

B
\(45 \%\)

C
\(50 \%\)

D
\(55 \%\)

Solution

Given,

Total amount = Rs. \(60000\)

The break-up of the cost of construction of a house (in degrees) for cement = \(72\)

The break-up of the cost of construction of a house (in degrees) for steel = \(54\)

Amount spent on cement steel and supervision \(=\frac{72+54+54}{360} \times 100\)

Required percentage \(=\frac{180}{360} \times 100\)

\(=\frac{18000}{360}\)

\(=50 \%\)
Question 4
4 / -1

Directions For Questions

Direction: Study the following pie chart carefully & answer the question given below it.

The pie chart given below shows the break-up of the cost of construction of a house (in degrees). Assuming that the total cost of construction is Rs. \(60000\), answer the question given below.

...view full instructions

The amount spent on labour exceeds the amount spent on supervision by:

A
Rs. \(200000\)

B
Rs. \(160000\)

C
Rs. \(120000\)

D
Rs. \(6000\)

Solution

Given,

Total cost = Rs. \(60000\)

The break-up of the cost of construction of a house (in degrees) for labour = \(90\)

The break-up of the cost of construction of a house (in degrees) for supervision = \(54\)

The difference in the angle of labour and supervision = \(90 - 54\)

\(=36\)

Amount \(=\frac{36}{360} \times 60000\)

\(=\frac{2160000}{360} \)

\(=\) Rs. \(6000\)
Question 5
4 / -1

Directions For Questions

Direction: Study the following pie chart carefully & answer the question given below it.

The pie chart given below shows the break-up of the cost of construction of a house (in degrees). Assuming that the total cost of construction is Rs. \(60000\), answer the question given below.

...view full instructions

What is the ratio of the combined expenditure on Supervision and Timber to the combined expenditure on Bricks and Cement?

A
\(7: 5\)

B
\(3: 4\)

C
\(4: 3\)

D
\(5: 7\)

Solution

Given,

The expenditure on Supervision \(=54\)

The expenditure on Timber \(=36\)

The expenditure on Bricks \(=54\)

The expenditure on Cement \(=72\)

The combined expenditure on Supervision and Timber \(=54+36\)

\(=90\)

The combined expenditure on Bricks and Cement \(=54+72\)

\(=126\)

So, the ratio of the combined expenditure on Supervision and Timber to the combined expenditure on Bricks and Cement \(=90:126 \)

\(=5: 7\)
Question 6
4 / -1

Directions For Questions

Direction: Below Bar graphs show the total investment(in thousand) of Ram and Amit in \(6\) schemes and \(\%\) of Ram’s investment respectively. Study the information carefully and answer the following question.

...view full instructions

Amount invested by Ram in scheme G is equal to the amount invested by him in scheme B. The ratio of interest per annum of scheme G and B are same. The only difference is that scheme G offers compound interest compounded annually, where as the scheme B offers simple interest. If the difference between the interests earned by Ram from both the schemes after \(2\) years is Rs. \(349.92\), then what is the rate of interest?

A
9%

B
7%

C
5%

D
11%

Solution

Let the interest be \(r\%\).

Amount invested by Ram in scheme B \(= 60\%\) of \(72000 =\) Rs. \(43200\)

Interest received on scheme B for \(1\)st year \(= 43200\left[1 + \frac{r}{100}\right] – 43200 = 43200 × r\%\)

Interest received on scheme B for \(2\)nd year \(= (43200 × r\%) + (r\% × r\% × 43200)\)

Principal for scheme G \(=\) Rs. \(43200\)

Simple interest for \(1\)st year \(= 43200 × r\%\)

Simple interest for \(2\)nd year \(= 43200 × r\%\)

Difference between both the interest \(= {(43200 × r\%) + (r\% × r\% × 43200)} – (43200 × r\%) = r\% × r\% × 43200\)

According to the question,

\(⇒ r\% × r\% × 43200 = 349.92\)

\(⇒ r^{2} × 432 = 34992\)

\(⇒ r^{2} = 81\)

\(⇒ r = 9\)
Question 7
4 / -1

Directions For Questions

Direction: Below Bar graphs show the total investment(in thousand) of Ram and Amit in \(6\) schemes and \(\%\) of Ram’s investment respectively. Study the information carefully and answer the following question.

...view full instructions

Amit invested in scheme F for \(4\)years if scheme F offers simple interest at \(7\%\) per annum for the first \(2\) years and then compound interest at \(10\%\) per annum (compounded annually) for the \(3\)rd year and \(4\)th year, then what will be the interest earned by Amit after \(4\) years?

A
\(14100\)

B
\(13500\)

C
\(13114\)

D
\(12600\)

Solution

Amit’s investment \(= 36\%\) of \(96000 =\) Rs. \(34560\)

Now, simple interest at \(7\%\) is being offered for \(2\) years,

Interest \(= \frac{\text{Principal × Rate × Time}}{100}\)

Interest \(= \frac{34560 × 7 × 2}{100} =\) Rs. \(4838.4 ≈\) Rs. \(4840\)

New Principal amount \(=\) Rs. \((34560 + 4840) = 39400\)

Now, the principal amount is Rs. \(4840\) on which compound interest at \(10\%\) is offered for \(2\) years,

Interest \(= \left[\text{Principal} \left(1 + \frac{r}{100}\right)^{t}\right] –\) Principal

Interest \(= \left[39400 (1 + \frac{10}{100})^{2}\right] – 39400 = 39400(1.21) – 39400 = 39400(1.21 – 1) =\) Rs. \(8274\)

Total interest \(=\) Rs. \((4840 + 8274)\) = Rs. \(13114\)
Question 8
4 / -1

Directions For Questions

Direction: Below Bar graphs show the total investment(in thousand) of Ram and Amit in \(6\) schemes and \(\%\) of Ram’s investment respectively. Study the information carefully and answer the following question.

...view full instructions

If scheme C offers compound interest (compounded annually) at \(12\%\) per annum, then what is the difference between interest earned by Ram and Amit by scheme C after \(2\) years? (approx)

A
Rs. \(1640\)

B
Rs. \(1628\)

C
Rs. \(1655\)

D
Rs. \(1590\)

Solution

Investment by Ram in scheme C \(= 40\%\) of \(32000 =\) Rs. \(12800\)

Investment by Amit in schemes C \(=\) Rs. (\(32000 – 12800) =\) Rs. \(19200\)

Difference in investment by Ram and Amit in scheme C \(=\) Rs. \((19200 – 12800) =\) Rs. \(6400\)

Now, Difference between the compound interest for \(2\) at \(12\%\) will be equal to the compound interest on Rs. \(6400\),

Interest \(= \left[\text{Principal} (1 + \frac{r}{100})^{t}\right] –\) Principal

Interest \(= [6400(1 + \frac{12}{100})^{2}] – 6400 = (6400 × 1.2544) – 6400 = 8028.16 – 6400 ≈ 1628\)
Question 9
4 / -1

Directions For Questions

Direction: Below Bar graphs show the total investment(in thousand) of Ram and Amit in \(6\) schemes and \(\%\) of Ram’s investment respectively. Study the information carefully and answer the following question.

...view full instructions

What is the respective ratio between total amount invested by Ram in scheme C and E together and total amount invested by Amit in the same schemes?

A
\(31 ∶ 44\)

B
\(33 ∶ 47\)

C
\(29 ∶ 44\)

D
\(35 ∶ 48\)

Solution

Investment by Ram in scheme C \(= 40\%\) of \(32000 =\) Rs. \(12800\)

Investment by Ram in scheme E \(= 42\%\) of \(64000 =\) Rs. \(26880\)

Ram’s total investment in scheme C and E \(=\) Rs. \((12800 + 26880) =\) Rs. \(39680\)

Investment by Amit in schemes C \(=\) Rs. \((32000 – 12800) =\) Rs. \(19200\)

Investment by Amit in scheme E \(=\) Rs. \((64000 – 26880) =\) Rs. \(37120\)

Total investment by Amit in scheme C and E \(=\) Rs. \((19200 + 37120) =\) Rs. \(56320\)

Required Ratio \(= 39680 ∶ 56320 = 3968 ∶ 5632 = 31 ∶ 44\)
Question 10
4 / -1

Directions For Questions

Direction: Below Bar graphs show the total investment(in thousand) of Ram and Amit in \(6\) schemes and \(\%\) of Ram’s investment respectively. Study the information carefully and answer the following question.

...view full instructions

Schemes A offers simple interest at a certain rate per annum. If the difference between the interest earned by both Ram and Amit from scheme A after \(4\) years is Rs. \(4032\), then what is the rate of interest?

A
20%

B
18%

C
15%

D
17.5%

Solution

As, Rate is same for both the person so let it be \(r\%\)

Now, according to the graphs,

Total investment by Ram and Amit in Scheme A \(=\) Rs. \(84000\)

Ram’s principal \(= 54\%\) of \(84000 = \frac{54}{100} × 84000 =\) Rs. \(45360\)

Amit’s principal \(=\) Rs. \((84000 – 45360) =\) Rs. \(38640\)

Difference between Principal amounts \(=\) Rs. \((45360 – 38640) =\) Rs. \(6720\)

As, Simple interest remain same for all the years,

Interest for \(1\) year \(= \frac{4032}{4} =\) Rs. \(1008\)

So, A simple interest of Rs. \(1008\) has been received on a principal of Rs. \(6720\),

\(⇒ SI = \frac{P × R × T}{100}\)

\(⇒ 1008 = \frac{6720 × r × 1}{100}\)

\(⇒ r = \frac{100800}{6720}\)

\(⇒ r = 15 \%\)