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Weekly Quiz Competition
  • Question 1
    4 / -0.83

    Which one of the following statements about electric or magnetic fields is not true?

    Solution

    CONCEPT:

    Electric Field Magnetic Field

    The electric force per unit positive charge at a given point is called an electric field. 

    A magnetic field is the measure of magnetic force at a particular point. 

    A charge kept static, or in constant motion or accelerated produces an electric field around it which changes with time. 

    A magnetic field is produced by a current-carrying wire which contains charges in motion. 

    So, basically, a charge in constant motion produces a magnetic field around it. 

    When the charge is accelerated the magnetic field varies with time. 

    EXPLANATION:

    • A charge in a static field produces an electric field only, a charge in motion produces both electric and magnetic fields. 
    • When the charge is accelerated the electric and magnetic fields produced are time-varying. 
    • Therefore, all-electric charges, whether static or in motion with respect to an observer gives rise to the electric field. Hence option 1 is correct.
    • If a charged particle is not moving i.e., in static conditions then it will not produce the magnetic field. Therefore option 2 is not true.

     

  • Question 2
    4 / -0.83

    The magnetic field inside a long current-carrying solenoid

    Solution

    Concept:

    Solenoid:

    • The solenoid is a type of electromagnet, the purpose of which is to generate a controlled magnetic field through a coil wound into a tightly packed helix.
    • The magnetic field is formed around the coil when an electric current passes through it and draws the plunger in.

    • The magnetic field at the center of the solenoid, B = μ0 nI, where, n = number of turns per unit length, I = current 

    Explanation:

    • The magnetic field inside a long straight solenoid-carrying current is the same at all points.
    • It is because the magnetic field in the solenoid is constant because the lines are completely parallel to each other.

     

  • Question 3
    4 / -0.83

    For a current carrying conductor, in the Maxwell's  'Right hand thumb law' the thumb points towards the

    Solution

    CONCEPT:

    • Right-hand thumb rule: According to this rule, if we imagine the linear wire conductor to be held in the grip of the right hand so that the thumb points in the direction of the current, then the curvature of the fingers around the conductor will represent the direction of the magnetic field lines.

    EXPLANATION:

    • From the above, it is clear that according to the Right-hand thumb rule, the thumb points in the direction of the electric current in a straight current-carrying wire.

    Additional Information

    • Fleming Left-hand rule gives the force experienced by a charged particle moving in a magnetic field or a current-carrying wire placed in a magnetic field.
      • It states that stretch the thumb, the forefinger, and the central finger of the left hand so that they are mutually perpendicular to each other.
      • If the forefinger points in the direction of the magnetic field, the central finger points in the direction of motion of charge, then the thumb points in the direction of force experienced by positively charged particles.

     

  • Question 4
    4 / -0.83

    An electron enters a uniform magnetic field at right angles to it as shown. The direction of force acting on the electron is (consider the plane of the page to be horizontal)

    Solution

    Concept:

    • Magnetic fields exert forces on moving charges, and so they exert forces on other magnets,
    • The magnitude of the magnetic force on a moving charge is given by 
    • Where, q is the magnitude of the electric charge, in C, V is the magnitude of the velocity of the charge, in m/s, B is the magnitude of the external magnetic field (T) in which the charge is moving, θ is the angle between v and B.

    The direction of the magnetic force on a moving charge is determined by using the Right-Hand-Rule

    • Place your right hand in the direction of v.  Next, close your hand in the direction of B.
    • Your thumb points in the direction of the force on a positive charge.
    • The direction of the force on a negative charge is opposite to the direction of the force on a positive charge.

    Explanation:

    • The direction of the magnetic force on a moving charge is determined by using the Right-Hand-Rule, 
    • When we place our right hand in the direction of v.  and close our hand in the direction of B.
    • Our thumb points in the direction vertically upward.
    • But the direction of the force on a negative charge is opposite to the direction of the force on a positive charge. and electron is a negative charge, so the direction of the magnetic force is vertically downward.

    OR

    From the palm rule, we can also calculate the force direction. If we point out the thumb direction in the direction of electron movement and the fingers in the direction of field direction, then the direction of palm gives the direction of force on the electron.

     

  • Question 5
    4 / -0.83

    Given below are two statements labelled as Assertion (A) and Reason (R)

    Assertion (A): A proton and an electron, with same momenta, enter in a magnetic field in a direction at right angles to the lines of the force. The radius of the paths followed by them will be same.

    Reason (R): Electron has less mass than the proton.

    Select the most appropriate answer from the options given below:

    Solution

    Explanation: 

    We know when a moving charge particle enters a magnetic field in a direction at right angles to the lines of force then the magnetic field changes the direction of charge.

    This leads to the circular motion of moving charge particles within the magnetic field.

    here, Centripetal force = Lorentz force

    where, v is the velocity of the charged particles, B is the magnetic field, m is the mass of

    the particle and r is the radius of the circular path and  θ is the angle between the

    magnetic field and velocity. 

    Solving for radius we get,

    Since momentum p and Magnetic field B are the same and charges on proton and electron both are the same then the radius will also be the same for both. hence, the assertion is true. 

    The mass of the proton is 1800 times the mass of the electron and hence reason is also true. 

    But the radius of the path does not depend on the mass and hence reason is not the correct explanation of the assertion

    Hence, the correct option is (2)

     

  • Question 6
    4 / -0.83

    The magnetic lines of force due to a bar magnet

    Solution

    CONCEPT:

    Magnetic Field Lines:

    • The magnetic field lines are invisible lines of magnetic force that never cross each other.
    • And can be drawn putting iron dust or compass in the magnetic field of the bar magnet.
    • Magnetic field lines are continuous and always form a unique closed loop around the magnet.
    • Magnetic field lines have a definite direction from North to South.
    • Magnetic field lines of force that are close together indicate a strong magnetic field.
    • Magnetic field lines of force that are farther apart indicate a weak magnetic field.

    EXPLANATION:

    • Magnetic field lines never intersect with each other.

    Important Point

    • Unlike poles means North and South attract each other.
    • Like poles means North and North repels each other.

     

  • Question 7
    4 / -0.83

    The magnitude of the magnetic field B at a distance r from an infinitely long straight conductor through which a current I is flowing, is given by

    Solution

    CONCEPT:

    The magnetic field at point O due to a straight conductor is given by:

    where B is the magnetic field at the center, μ0 permeability of the medium I is the current in the circular loop, and d is the distance from the wire to that point.

    EXPLANATION:

    The magnitude of the magnetic field B at a distance r from an infinitely long straight conductor through which a current I is flowing is given by:

    Hence the correct answer is option 1.

     

  • Question 8
    4 / -0.83

    Which of the following statement is not true; magnetic field at the centre of current carrying loop:-

    Solution

    Concept:

    Current Carrying Coil: 

    • When an electric current is passed through a closed circular current carrying wire then the magnetic field is observed in the surrounding which is strong at the center as compared to outside.
    • The current carrying coil is just like a magnet.

    Magnetic Field: 

    • The field around a moving charge or magnetic material up to which magnetic effect or force due to magnetism can be experienced is called a magnetic field.
    • The magnetic field at the center the of circular current carrying coil is given by the mathematical expression:

    • where I is current through the circular loop, N is the total no of turns in the circular current carrying loop and , r is the radius of the circular current carrying loop and μ0 is the permeability of free space

    Explanation:

    Let us consider a circular loop of wire of radius r carrying current I.

    We have to calculate the magnetic field at the center of the loop. 

    First of all the entire loop is divided into a large o of small current elements.

    We have considered one such small current element  of the loop.

    According to Biot-Savart law, the magnetic field at the center due to this element is

    The magnetic field  at the center of the current carrying loop

    • proportional to current (I)
    • inversely proportional to radius (r)
    • proportional to the number of turns (N)

    Important Points

    Biot-Savart Law:

    • T he law that gives the magnetic field generated by a constant electric current is Biot-savart law.
    • Let us take a current carrying wire of current I and we need to find the magnetic field at a distance r from the wire then it is given by:

    Where,

    μ0 = the permeability of free space/vacuum (4π × 10-7 T.m/A),

    dl = small element of wire

     the unit position vector of the point where we need to find the magnetic field.

     

  • Question 9
    4 / -0.83

    If the forefingers shows the direction of the magnetic field and the thumb indicates the motion of the conductor, then, according to Fleming's left hand rule, what does the middle finger point at?

    Solution

    CONCEPT:

    • Fleming Left-hand rule gives the force experienced by a charged particle moving in a magnetic field or a current-carrying wire placed in a magnetic field.
    • It states that "stretch the thumb, the forefinger, and the central finger of the left hand so that they are mutually perpendicular to each other.
    • If the forefinger points in the direction of the magnetic field, the central finger points in the direction of motion of charge, then the thumb points in the direction of force experienced by positively charged particles."

    EXPLANATION:

    • According to question
    1. Forefinger (Index finger): Represents the direction of the magnetic field (magnetic flux)
    2. Middle finger: Represents the direction of motion of charge (current). Therefore option 2 is correct.
    3. The thumb is pointing out of the paper: Represents the direction of force experienced by positively charged particles.

     

  • Question 10
    4 / -0.83

    A circular coil of radius 0.50 m and 100 turns, carrying a current of 80 mA, is placed such that the normal to its plane makes an angle of 30° with a uniform magnetic field of 4.0 T. The magnitude of torque acting on the coil is:

    Solution

    Concept:

    Torque:

    • ​ It is defined as the product of the magnitude of the force and the perpendicular distance of the line of action of a force from the axis of rotation.
    • Formula, τ = rFsinθ , where r = perpendicular distance, F = force, θ = angle between force and perpendicular distance
    • The SI unit of torque is N-m.

    Torque in a current loop:

    • Let us consider a rectangular loop such that it carries a current of magnitude I.

    • If we place this loop in a magnetic field, it experiences a torque but no net force, quite similar to what an electric dipole experiences in a uniform electric field.
    • The torque acting on the coil is calculated as, τ = NIAB sinθ where N = number of turns, I = current, A = area of the loop, B = magnetic field, θ = angle between area and magnetic field. 

    Calculation:

    Given,

    The number of turns, N = 100 turns

    The current in the coil, I = 80 mA

    Angle, θ = 30º

    The radius of the circular coil, r = 0.50 m

    The magnitude of the magnetic field, B = 4.0 T

    The torque acting on the coil is calculated as, τ = NIAB sinθ 

    τ = 100 × 80 × 10-3 × π × (0.50)× 4.0 × sin 30º

    τ = 4π N m

    Hence, the magnitude of torque acting on the coil is 4π N m.

     

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