Self Studies

Solid State Test - 12

Result Self Studies

Solid State Test - 12
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

     For which type of cubic lattice, a = 2r?

    Solution

    In simple cubic lattice the side of the solid structure is equal to twice the radius of atom. Hence the correct answer is simple cubic.

  • Question 2
    1 / -0

    Packing efficiency of body centred cubic unit cell is:

    Solution

    The packing efficiency of both types of close packed structure is 74%, i.e. 74% of the space in hcp and ccp is filled. The hcp and ccp structure are equally efficient; in terms of packing. The packing efficiency of simple cubic lattice is 52.4%. And the packing efficiency of body centered cubic lattice (bcc) is 68%.

  • Question 3
    1 / -0

    Packing efficiency in a unit cell is never 100% because constituent particles are assumed to be:

    Solution

    The constituent particles i.e. atoms, molecules and ions are assumed to be spheres.

  • Question 4
    1 / -0

    If r is radius of void and R is radius of the sphere, then for an atom to ocuppy an octahedral void which relation holds true?

    Solution

    Let the radius of the octahedral void be r and radius of the atoms in close-packing be R and the edge length be a.


    In the right angle triangle ABC,

    AB = BC = a

    For the diagonal AC,

    Using Pythagoras Theorem we get;

    Also, 

    And, AB = 2R

    AC = R + 2r + R = 2R + 2r

    r = 0.414R

    Hence, the relation is r = 0.414R.

  • Question 5
    1 / -0

     Which type of void is represented by the following diagram?

    Solution

    A tetrahedral void is formed when one sphere or particle is placed in the depression formed by three particles.
    Definition of Tetrahedral Void: The vacant space or void among the four constituent particles having tetrahedral arrangement in the crystal lattice is called tetrahedral void.

  • Question 6
    1 / -0

     HCP structure is present in:

    Solution

    • Magnesium has hexagonal close-packed (HCP) crystal structure.
    • Bonding is non-directional metallic bonding.
    • Magnesium is metallic solid. The units occupying lattice sites are Mg ions and these ions are surrounded by mobile or delocalised electrons.
    • The arrangement of ions in one plane the arrangement of ions is a hexagonal array or closed packed layer. Thus each metal ion is touching six adjacent ions in one plane.

  • Question 7
    1 / -0

    If r is the radius of the void and R is the radius of the sphere, what is AC in the following diagram?

    Solution

    AC = Diameter of void + (2× Radius of sphere) 》AC = 2r + 2R = 2(R+r)

  • Question 8
    1 / -0

    Which of the following shows maximum packing efficiency?

    Solution

    HCP = 74% packing efficiency
    BCC = 68% packing efficiency
    Simple cubic = 52.4% packing efficiency 

  • Question 9
    1 / -0

     The number of atoms in each unit cell in ccp structure is:

    Solution

    In ccp structure: number of atoms per unit cell is

    8 corners × 1/8 per corner atom = 8 × 1/8 = 1 atom
    6 face-centred atoms × 1/2 atom per unit cell = 3 atoms
    Therefore, the total number of atoms in a unit cell = 4 atoms.

  • Question 10
    1 / -0

    The number of atoms per unit cell in a body centred cubic arrangement is:

    Solution

    For a bcc unit cell, number of atoms per unit cell = (8 *1/8) + 1 = 2

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now