p-Block Elements Test

Result

p-Block Elements Test - 20

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Weekly Quiz Competition

Question 1
1 / -0

Hot conc. H₂SO₄ acts as moderately strong oxidising agent. It oxidises both metals and nonmetals. Which of the following element is oxidised by conc. H₂SO₄ into two gaseous products?

A
Cu

B
S

C
C

D
zn

Solution

Option A: Cu + 2H₂SO₄ → CuSO₄ + SO₂ + 2H₂O
Option B: S + 2H₂SO₄ → 2SO₂ +2H₂O
Option C: C + 2H₂SO₄ → CO₂ + 2SO₂ + 2H₂O
Option D: Zn + 2H₂SO₄ → ZnSO₄ + SO₂ + 2H₂O
Hence, option C is correct.
Question 2
1 / -0

Correct order of 2nd ionisation energy of C, N, O and F is

A
N > F > O > C

B
O > F > N > C

C
F > O > N > C

D
O > F > C > N

Solution

The second ionization energy refers to the energy required to remove the electron from the corresponding monovalent cation of the respective atom.
It is expected to increase from left to right in the periodic table with the decrease in atomic size.
Since the Oxygen atom gets a stable electronic configuration, 2s²2p³ after removing one electron, the O⁺ shows greater ionization energy than F⁺ as well as N⁺.
Thus, correct order will be: O > F > N > C
Question 3
1 / -0

Which trend enthalpy is correct ?

A
N — O > P — O

B
N— F > P — F

C
N ≡ N > P ≡ P

D
N—N > P—P

Solution

Bonds → Bond enrgy
N-O → 201 kJ/mol
P-O → 340 kJ/mol
N-F → 272 kJ/mol
P-F → 490 kJ/mol
N≡N → 946 kJ/mol
P≡P → 490 kJ/mol
N-N → 160 kJ/mol
P-P → 209 kJ/mol
Hence option C is correct.
Question 4
1 / -0

Boiling Point of liquid nitrogen is

A
4 K

B
20 K

C
77 K

D
87 K

Solution

Liquid nitrogen is a cryogenic fluid that can cause rapid freezing on contact with living tissue.
The temperature is held constant at 77 K by slow boiling of the liquid, resulting in the evolution of nitrogen gas.
Question 5
1 / -0

Oxidation of ammonia with CuO produce a gaseous chemical which can also be obtained by:

A
Heating ammonium nitrate.

B
Reacting excess ammonia with chlorine.

C
Heating potassium dichromate.

D
Catalytic oxidation of ammonia.

Solution

Actually when ammonia is passed through a solution of calcium hypochlorite (bleaching powder), bromide water or passed over heated Cu oxide, it is oxidized to dinitrogen gas.
2NH₃+ 3CuO → 3Cu + 3H₂O + N₂
8NH₃(excess) + 3Cl₂ → 6NH₄Cl + N₂
Question 6
1 / -0

Which of the following molecular species has unpaired electron(s) ?

A
N₂

B
O₂

C
NO⁺

D
CN^-

Solution

contains two unpaired electrons and is paramagnetic in nature. On the other hand, , and contains all paired electrons and are diamagnetic in nature.
Question 7
1 / -0

Which is the correct order w.r.t the given property?

A
N > P > As > Sb > Bi (Atomic mass)

B
N > P > As > Sb = Bi (Electronegativity)

C
N > P > As > Sb = Bi (Covalent radii)

D
N = P > As > Sb > Bi (Density)

Solution

Only electronegativity of the given 4 decreases down the group whilst all the others increase or stay the same down the group.
Question 8
1 / -0

The ratio of bond pairs and lone pairs in a P₄ molecule is

A
1:1

B
2:3

C
3:2

D
4:1

Solution

P₄ has six P-P single bonds and four lone pair of electrons.
Ratio: 6/4 = 3/2 i.e. 3:2