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Atomic Structure Test - 1

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Atomic Structure Test - 1
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  • Question 1
    1 / -0

    Which electronic level would allow the hydrogen atom to absorb a photon but not to emit a photon?

    Solution

    Ground state of hydrogen atom, i.e., 1s, because by absorbing photon it can go upto any higher level, while it cannot emit a photon because lower level than 1s in not possible.

     

  • Question 2
    1 / -0

    Rutherford’s alpha particle scattering experiment eventually led to the conclusion that

    Solution

    Rutherford’s experiment was to find the position of protons and electrons in the atom.

     

  • Question 3
    1 / -0

    Which of the following does not characterize X-rays?

    Solution

    X- rays are not deflected by  electric by and magnatic fields 

     

  • Question 4
    1 / -0

    The electrons, identified by quantum numbers n and l, (i) n = 4, l = 1, (ii) n = 4, l = 0,  (iii) n = 3, l = 2 and  (iv) n = 3, l = 1 can be placed in order of increasing energy, from the lowest to highest, as

    Solution

    Reason of correctness

    On the basis of (n + l) rule

    (i)  Value of (n + l) = 4 + 1 = 5     (ii)Value of (n + l) = 4 + 0 = 4

    (iii) Value of (n + l) = 3 + 2 = 5  (iv)Value of (n + l) = 3 + 1 = 4

    On the basis of (n + l) rule

    In these (n + l) is lower for (ii) and (iv) but both are equal. In these n is minimum for (iv)

    Hence, energy order = (iv) < (ii)

    Similarly in (i) and (iii), (iii) < (i)

    Hence, correct order of energy (iv) < (ii) < (iii) < (i)

     

  • Question 5
    1 / -0

    If the nitrogen atom had electronic configuration 1s7, it would have energy lower than that of the normal ground state configuration 1s2 2s2 2p3, because the electrons would be closer to the nucleus, yet 1s7 is not observed because it violets

    Solution

    On the basis of Pauli’s exclusion principle, not more than two electrons can enter in an orbital. Hence, seven electrons (as 1s7) in an orbital violates Pauli’s exclusion principle.

     

  • Question 6
    1 / -0

    Total number of nodes in 5d sub-shell will be

    Solution

    Total number of nodes given by (n – 1), hence 4

     

  • Question 7
    1 / -0

    An electron in H-atom in its ground state absorbs 1.50 times as much as energy as the minimum required for its escape (13.6 eV) from the atom. Thus KE given of emitted electron?

    Solution

    Energy in ground state = 13.6 eV

    Energy absorbed = 1.5 × 13.6 eV                                 = 20.4 eV

    Kinetic energy of emitted e¯ is  = (– 13.6 + 20.4) eV

                                                    =  6.8 eV

     

     

  • Question 8
    1 / -0

    A continuum in spectrum is observed due to the following

    Solution

    Quantized discrete energy states are due to presence of energy levels. Once electron is completely free from nucleus, it will not be associated with discrete energy states.

     

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