Biology Test 121

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Biology Test 121

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Weekly Quiz Competition

Question 1
4 / -1

The presence of bladder is a common feature of

A
Teleostomi

B
Agnathostomes

C
Holocephali

D
Elasmobranchii

Solution

Teleost fishes (bony fishes) have developed an air bladder attached to the digestive system. It helps to give buoyancy.

Hence, the correct option is (A).
Question 2
4 / -1

RQ (Respiratory Quotient) is infinite

A
if respiratory substrate is carbohydrate

B
if respiratory substrate is fat

C
if respiratory substrate is an organic acid

D
in anaerobic respiration
Question 3
4 / -1

Colchicine is employed to diploid a haploid cell

A
inhibits karyokinesis

B
inhibits formation of mitotic spindle

C
allows replication of DNA twice in one cell cycle

D
inhibits formation of centromere

Solution

Colchicine, a drug, which inhibits spindle fibre formation during mitosis and halts cell division at metaphase. This often will result in a doubling of the chromosome number since colchicine typically inhibits cytokinesis, but not karyokinesis. The doubled chromosomes will fuse within a single nucleus, thus diploidising the haploid cell. Hence, the correct option is (B).
Question 4
4 / -1

The exchange of chromosomal segments between non-homologus chromosomes is called

A
inversion

B
heterozygosity

C
deletion

D
translocation

Solution

The exchange of segments of two non-homologous chromosomes is termed as translocation. In genetics, a chromosome translocation is a chromosome abnormality caused by rearrangement of parts between nonhomologous chromosomes

Hence, the correct option is (D).
Question 5
4 / -1

What is the process of fusion of protoplasms between two motile or non-motile gametes called?

A
Karyogamy

B
Xenogamy

C
Plasmogamy

D
Autogamy

Solution

The process of fusion of protoplasms between two motile or non-motile gametes is called plasmogamy.

Hence, the correct option is (C).
Question 6
4 / -1

Which of the following organisms is ammonotelic?

A
Man

B
Bony fish

C
Cartilaginous fish

D
Bird

Solution

An ammonotelic organism excretes nitrogenous waste as soluble ammonia. Most of the aquatic animals including protozoans, crustaceans, platyhelminths, cnidarians, poriferans, echinoderms, fishes, larvae / tadpoles of amphibians are ammonotelic.

Among the given options, Bony fish is ammonotelic.

Hence, the correct option is (B).
Question 7
4 / -1

Which of the following structures temporarily stores sperms?

A
Vas deferens

B
Epididymis

C
Vasa efferentia

D
Urinary bladder

Solution

Sperm are produced in tightly-coiled tubes inside of the testes called seminiferous tubules. The epididymis temporarily stores p y mature sperm cells. Each sperm cell has a flagellum for locomotion or movement. A tube called the vas deferens passes from each epididymis into the body

Hence, the correct option is (B).
Question 8
4 / -1

A radioisotope used to label proteins differently from nucleic acids is

A
C-14

B
N-15

C
P-32

D
S-35

Solution

A radioisotope used to label proteins differently from nucleic acids is 35S.

Sulphur-35 is used to label proteins and nucleic acids. Cysteine is an amino acid containing a thiol group, which can be labelled by S-35. For nucleotides that do not contain a sulphur group, the oxygen on one of the phosphate groups can be substituted with a sulphur.
Hence, the correct option is (D).
Question 9
4 / -1

By which of the following processes an amino group from amino acid is transferred to produce a keto acid?

A
Condensation

B
Transamination

C
Deamination

D
Hydrolysis

Solution

Transamination, a chemical reaction that transfers an amino group to a ketoacid to form new amino acids. This pathway is responsible for the deamination of most amino acids. This is one of the major degradation pathways which convert essential amino acids to nonessential amino acids.

Transamination in biochemistry is accomplished by enzymes called transaminases or aminotransferases. α-ketoglutarate acts as the predominant amino-group acceptor and produces glutamate as the new amino acid.
Hence, the correct option is (B).
Question 10
4 / -1

The splitting of a 6-carbon glucose molecule into molecules with 2-3 carbons called pyruvic acid takes place during

A
EMP pathway

B
Krebs' cycle

C
Calvin's cycle

D
Sigmoid curve

Solution

Glycolysis (Embden–Meyerhof–Parnas (EMP pathway)) is the metabolic pathway that converts glucose C₆H₁₂O₆ into pyruvate, CH3COCOO⁻ + H^+.

Hence, the correct option is (A).

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Biology Test 121

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Biology Test 121

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SHARING IS CARING

Question 1

Teleostomi

Agnathostomes

Holocephali

Elasmobranchii

Solution

Question 2

if respiratory substrate is carbohydrate

if respiratory substrate is fat

if respiratory substrate is an organic acid

in anaerobic respiration

Question 3

inhibits karyokinesis

inhibits formation of mitotic spindle

allows replication of DNA twice in one cell cycle

inhibits formation of centromere

Solution

Question 4

inversion

heterozygosity

deletion

translocation

Solution

Question 5

Karyogamy

Xenogamy

Plasmogamy

Autogamy

Solution

Question 6

Man

Bony fish

Cartilaginous fish

Bird

Solution

Question 7

Vas deferens

Epididymis

Vasa efferentia

Urinary bladder

Solution

Question 8

C-14

N-15

P-32

S-35

Solution

Question 9

Condensation

Transamination

Deamination

Hydrolysis

Solution

Question 10

EMP pathway

Krebs' cycle

Calvin's cycle

Sigmoid curve

Solution

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