NEET Test 103

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NEET Test 103

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Weekly Quiz Competition

Question 1
4 / -1

A 5 molar solution of H₂SO₄ is diluted from 1 litre to a volume of 10 litres, the normality of the resulting solution will be

A
0.1 N

B
5 N

C
0.5 N

D
1 N

Solution

Given,

M₁=5 molar

V₁=1 litre

V₂=10 litre

According to Dilation Formula,

M₁ V₁= M₂ V₂

⇒M₂= 0.5

Normality = Molarity × Equivalent number

Equivalent number refers to how many ions are acting in the solution, the number of those ions is called the gram equivalent number.

Here, the Equivalent number = 2

N₂= 0.5×2 = 1.0 N

Hence, the correct option is (D).
Question 2
4 / -1

When phenol is treated with CHCl₃ and NaOH, the product formed is:

A
Benzaldehyde

B
Salicylaldehyde

C
Salicylic acid

D
Benzoic acid

Solution

When phenol is treated with CHCl₃ and NaOH the product formed is salicylaldehyde, this reaction is known as Reimer-Tiemann reaction.
Question 3
4 / -1

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of H₂ gas at the cathode is: (1 Faraday = 96500Cmol⁻¹)

A
9.65 ×10⁴ sec

B
19.3 ×10⁴ sec

C
28.95 ×10⁴ sec

D
38.6 ×10⁴ sec

Solution
Question 4
4 / -1

Diatoms stay afloat due to:

A
Pseudopodia

B
Flagella

C
Stored lipids

D
All the above

Solution

In diatoms, the major carbon storage is triacylglycerides (TAGs) and fatty acids which usually make up 15 − 25% of dry biomass. These stored lipids of diatoms help them float on the water surface. The lipid increases the buoyancy and helps avoid sinking in water. Most diatoms are non - motile and lack flagella or pseudopodia and hence they move through the water currents.

Hence, the correct option is (C).
Question 5
4 / -1

Smooth ER does not play an important role in the biosynthesis of which of the following?

(a). Glycolipids

(b). Phospholipids

(c). Polysaccharides

(d). Cholesterol

A
Only (a) and (b)

B
Only (a),(b) and (c)

C
Only (a) and (c)

D
Only (c)

Solution

When the cells are grown on a carbon source different than glucose, then polysaccharides are synthesized using a different pathway. Gluconeogenesis (abbreviated GNG) is a metabolic pathway that results in the generation of glucose from non-carbohydrate carbon substrates such as phosphoenolpyruvate (PEP).

Hence, the correct option is (D).
Question 6
4 / -1

A cross between a pea plant with purple flower (PP) and a pea plant with white flower (pp), what will be the phenotypic ratio?

A
All white

B
All purple

C
Half purple, half white

D
1 PP, 2 Pp, 1 pp

Solution

A cross between a pea plant with purple flower (PP) and a pea plant with white flower (pp),. The phenotypic ratio will be all purple.

The offsprings are of Pp (heterozygote) genotype. According to Mendel’s law of dominance, in a heterozygote one trait will hide or mask the characteristics of another trait of the same characteristic. Only the dominant allele can express itself. The recessive allele can only express itself in monozygotic conditions. Here, the purple colour trait is dominant therefore hides the white colour trait for the same characteristic that is flower colour. So, all the flowers are purple.

Hence, the correct option is (B).
Question 7
4 / -1

Which of the following hormones promote(s) growth in plants?

a. Auxins

b. Cytokinins

c. Abscisic acid

A
Only a

B
Only a and b

C
Only b

D
Only b and c

Solution

Auxins are hormones that stimulate growth and are produced in immature parts of plants. They were the first group of hormones studied in plants. Cytokinins are chemicals produced in the roots which stimulate growth and have anti-aging effects.

Hence, the correct option is (B).
Question 8
4 / -1

The IUPAC name of the given compound is:

A
4-hydroxy-1-methylpentanal

B
3, 4-dihydroxy-2-methylpentanal

C
2-hydroxy-4-methylpentanal

D
2, 3-dihydroxy-4-methylpentanal

Solution

The IUPAC name of the given compound is 3, 4-dihydroxy-2-methylpentanal.

Aldehyde has a higher priority than alcohol, so the numbering is done as shown in the figure. The longest continuous chain contains 5 carbon atoms and at 3rd and 4th position hydroxy group is present. At 2nd carbon atom, one methyl group is present. Alphabetically 'h' comes first then 'm'.

Hence, the correct option is (B).
Question 9
4 / -1

A wheel is rotating at the rate of 33 revolution/min. if it comes to a stop in 20 seconds. Then the angular retardation will be

A
0

B

C

D

Solution

Given that,

The initial angular velocity of the wheel, (ω_i)=33 revolution/min

The Final angular velocity of the wheel, (ω_f)=0

Time taken by wheel to stop t = 20 s

We know that,

The initial angular velocity in rad/s,(ω_i) is given by

= 33 × 2π/60 (2π/60 is the conversion factor from revolution/minute to rad/s)

=1.1π rad/s

The angular retardation can be calculated by using the formula,

(Since retardation is mentioned, hence we have to take the negative value of alpha and not positive value).

ω_f=ω_i−αt (Putting the values given in the question, we have the following)

⇒ 0 = 1.1π − α × 20

⇒ α = 1.1π/20

=11π/200 rad/s²

Hence, the correct option is (D).
Question 10
4 / -1

Which of the following are examples of framework silicates?

1. Feldspars

2. Zeolites

3. Mica

4. Thortveitite

A
1 and 2 only

B
1 and 3 only

C
1 and 4 only

D
2 and 3 only

Solution

Feldspar, any of a group of aluminosilicate minerals that contain calcium, sodium, or potassium. Feldspars make up more than half of Earth's crust, and professional literature about them constitutes a large percentage of the literature of mineralogy.

The mineralogical composition of most feldspars can be expressed in terms of the ternary system Orthoclase (KAlSi₃O₈), Albite (NaAlSi₃O₈), and Anorthite (CaAl₂Si₂O₈). Chemically, the feldspars are silicates of aluminum, containing sodium, potassium, iron, calcium, or barium or combinations of these elements.

Zeolites transform to other minerals under weathering, hydrothermal alteration, or metamorphic conditions.

Zeolites are crystalline solids structures made of silicon, aluminum, and oxygen that form a framework with cavities and channels inside where cations, water, and/or small molecules may reside. They are often also referred to as molecular sieves.
Hence, the correct option is (A).