NEET Test 77

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NEET Test 77

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Weekly Quiz Competition

Question 1
4 / -1

Haemozoin is a toxic substance released upon which of the following events?

A
Rupture of liver cells

B
Rupture of cells of gut epithelium

C
Rupture of RBCs

D
Rupture of cells of salivary glands

Solution

The Plasmodium species during malarial formation, metabolize hemoglobin and other RBC proteins to create a toxic pigment called hemozoin. Haemozoin is a waste product formed when the parasite digests the blood. The parasite digests the hemoglobin of the blood and release high quantities of free heme. This heme released is a non-protein component of hemoglobin. The haemozoin is, therefore, a product of the erythrocyte lysis released from the food vacuole into circulation.

Hence, the correct option is (C).
Question 2
4 / -1

The values of the currents i₁ and i₂ flowing through the resistors R₁(= 10Ω ) and R₂(=30Ω) respectively, in the circuit diagram with E₁=3V,E2 =3V and E₃=2V, are:

A
0.2A, 0.1A

B
0.4A, 0.2A

C
0.1A, 0.2A

D
0.2A, 0.4A

Solution
Question 3
4 / -1

Elimination reaction of 2-Bromo-pentane to form pent-2-ene is:

(a) β-Elimination reaction

(b) Follows Zaitsev rule

(c) Dehydrohalogenation reaction

(d) Dehydration reaction

A
(a), (b), (c)

B
(a), (c), (d)

C
(b), (c), (d)

D
(a), (b), (d)
Question 4
4 / -1

Which of the following compounds can form a Zwitterion?

A
Benzoic acid

B
Aniline

C
Glycine

D
Acetanilide

Solution

Amino acids form Zwitterion ion. Among the given options, Glycine is an amino acid and hence, it forms Zwitterion ion.

Hence, the correct option is (C).
Question 5
4 / -1

A mixture of N₂ and Ar gases in a cylinder contains 7 g of N₂ and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N₂ is:

[Use atomic masses (in g mol⁻¹) : N=14, Ar=40]

A
9 bar

B
12 bar

C
15 bar

D
18 bar

Question 6

4 / -1

Match the list-I with List-II

	List-I (Electrode)		List-II (Type)
1.	Calomel	P.	Reference
2.	Glass	Q.	Redox
3.	Hydrogen	R.	Membrane
4.	Quinhydrone	S.	Gas

1-P, 2-R, 3-S, 4-Q

1-Q, 2-P, 3-S, 4-R

1-R, 2-Q, 3-P, 4-S

1-S, 2-P, 3-R, 4-Q

Solution

	List-I (Electrode)		List-II (Type)
1.	Calomel	P.	Reference
2.	Glass	Q.	Membrane
3.	Hydrogen	R.	Gas
4.	Quinhydrone	S.	Redox

Hence, the correct option is (A).

Question 7
4 / -1

A vessel contains a mixture of one mole of oxygen and two moles of nitrogen at 300 K. The ratio of the rotational kinetic energy per O₂ molecule to that per N₂ molecule is

A
1 : 1

B
1 : 2

C
2 : 1

D
It depends on the moment of inertia of the two molecules

Solution

The law of euipartition of energy states that 'For a dynamical system in thermal equilibrium, the energy of a system is equally distributed among its various degrees of freedom and the

energy associated with each degree of freedom per molecule is 1/2k × T

In this case, O₂ and N₂ both have two degrees of rotational kinetic energy and since the temperature is also same, the ratio of the average rotational kinetic energy is 1:1

Hence, the correct option is (A).
Question 8
4 / -1

The total number of ions present in 111 g of CaCl₂ is:

A
One Mole

B
Two Mole

C
Three Mole

D
Four Mole

Solution

Molecular weight of

CaCl₂ = 111 g/mol

Ions in one calcium chloride molecule = Ca⁺² + 2Cl^–

= 3 ions

Now no. of molecules in 111 g/mol of CaCl₂ = Avogadros number

= 6.02 × 10²³ molecules

So number of ions in 111 g/mol of CaCl₂

= 3 × 6.02 × 10²³ ions

= 3 moles.
Hence, the correct option is (C).
Question 9
4 / -1

At rest, a well-trained athlete will have a heart rate ______ a normal person.

A
Higher than

B
Lower than

C
Same as

D
Incomparable to

Solution

In an adult, at rest, the resting heart rate ranges from 60-100 beats/minute. The vigorous regular exercises which an athlete does helps the heart to function better and pump more blood at a lower rate as compared to the normal sedentary person. The aerobic exercises done by the athletes helps to strengthen the heart muscle and thus reducing the heart rate at rest which otherwise would be higher in a normal adult.

Hence, the correct option is (B).
Question 10
4 / -1

A resonance air column of length 40 cm resonates with a tuning fork of frequency 450 Hz. Ignoring end corrections, the velocity of sound in air will be:

A
1020 m / s

B
920 m / s

C
820 m / s

D
720 m / s

Solution

We know that the minimum length of the air column tube corresponds to the fundamental mode of vibrations. Hence, by ignoring end corrections-

Length of column =40 cm

=0.4 m

Frequency of tuning fork =450 m

Using the formula, n=v / 4I

V = 450×4×0.4

=720 m/s

Hence,the correct option is (D).

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Re-Attempt Weekly Quiz Competition

NEET Test 77

Result

NEET Test 77

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SHARING IS CARING

Question 1

Rupture of liver cells

Rupture of cells of gut epithelium

Rupture of RBCs

Rupture of cells of salivary glands

Solution

Question 2

0.2A, 0.1A

0.4A, 0.2A

0.1A, 0.2A

0.2A, 0.4A

Solution

Question 3

(a), (b), (c)

(a), (c), (d)

(b), (c), (d)

(a), (b), (d)

Question 4

Benzoic acid

Aniline

Glycine

Acetanilide

Solution

Question 5

9 bar

12 bar

15 bar

18 bar

Question 6

1-P, 2-R, 3-S, 4-Q

1-Q, 2-P, 3-S, 4-R

1-R, 2-Q, 3-P, 4-S

1-S, 2-P, 3-R, 4-Q

Solution

Question 7

1 : 1

1 : 2

2 : 1

It depends on the moment of inertia of the two molecules

Solution

Question 8

One Mole

Two Mole

Three Mole

Four Mole

Solution

Question 9

Higher than

Lower than

Same as

Incomparable to

Solution

Question 10

1020 m / s

920 m / s

820 m / s

720 m / s

Solution

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