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Physics Test 96

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Physics Test 96
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The height of a mercury barometer is 75 cm at sea level and 50 cm at the top of a hill. Ratio of density of mercury to that of air is 104. The height of the hill is:

    Solution

    P0 = ρHg g (75 cm)                      ...(1)

    (P0 – ρgh) = ρHg g (50 cm)          ...(2)

    from (1) & (2)

    ρgh = ρHg g (25 cm)

    ρh = ρHg  (1/4 m)

    h =  104/4 = 2500m

       = 2.5 km

     

  • Question 2
    4 / -1

    There are two identical small holes of area of cross-section a on the opposite sides of a tank containing a liquid of density ρ. The difference in height between the holes is h. Tank is resting on a smooth horizontal surface horizontal force which will has to be applied on the tank to keep it in equilibrium is :

    Solution

    F = ρaV12 – ρaV22

       = ρa[2g(h + y) – 2gy]

       = 2 ρagh

     

  • Question 3
    4 / -1

    A liquid is flowing in a horizontal uniform capillary tube under a constant pressure difference P. The value of pressure for which the rate of flow of the liquid is doubled when the radius and length both are doubled is:

    Solution

     

  • Question 4
    4 / -1

    In a young double slit experiment the angular width of fringe formed on a distant screen is 0.2 radian. Find the distance between the two slits if wavelength of light used is 6000 Å ?

    Solution

     

  • Question 5
    4 / -1

    In a Y.D.S.E, light has a frequency of 9 × 1014 Hz. The distance between the centres of adjacent bright fringes is 1 mm. If the screen is 2m away then find the distance between the slits.

    Solution

     

  • Question 6
    4 / -1

    The path difference between two interfering waves at a point on screen is 171.5 times the wavelength. If the path difference is 0.01372 cm. Find the wavelength ?

    Solution

     

  • Question 7
    4 / -1

    White light is incident on a soap film of refractive index 4/3 at an angle of refraction 30o. The reflected light is observed to have a dark band for wavelength 4 × 10–5 cm. Calculate the minimum thickness of the film ?

    Solution

     

  • Question 8
    4 / -1

    Light of wavelength 4000Å is incident normally on a slit of width 16 × 10–5 cm. Find out the angular position of second minimum from central maximum?

    Solution

    a sin θ = 2λ

    θ = 30o

     

  • Question 9
    4 / -1

    Calculate the limit of resolution of a microscope if an object of numerical aperture 0.1 is viewed by using light of wavelength 6 × 10–7 m

    Solution

     

  • Question 10
    4 / -1

    Refractive index of glass is 1.5 calculate the angle of polarisation for light reflected from the surface of slab. (tan–1 1.5 = 56.3)

    Solution

    θ = tan–1(µ) = tan–1(1.5) = 56.3

     

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