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Thermodynamics Test - 9

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Thermodynamics Test - 9
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  • Question 1
    1 / -0

    The compounds C2H5OC2H5 and CH3OCH2CH2CH3 are

    Solution

    Here, ether is functional group and whenever there is change around same functional group they are metamers to each other.
    These are chain as well as metamers but priority is given to metamerism even if we have to choose between metamer and position then, again metamer is to be opted first.

  • Question 2
    1 / -0

    The number of isomers of pentane is

    Solution

    Pentane (C5H12) is an organic compound with five carbon atoms. Pentane has three structural isomers that are n-pentane, Iso-pentane (methyl butane) and neopentane (dimethylpropane).

  • Question 3
    1 / -0

    How many minimum no. of C-atoms are required for position & geometrical isomerism in alkene?

    Solution

    The smallest alkene showing geometrical isomerism is but−2−ene (4−C atoms)
    The smallest alkene showing position isomerism is butene (4−C atoms), where the position of double bonds may vary.
    Hence, answer is 4,4

  • Question 4
    1 / -0

    How many structural formula are possible when one of the hydrogen is replaced by a chlorine atom in anthracene?

    Solution


    Position 1,4,5,8 are equal.
    Similarly 2,3,6,7 are equal.
    Position 9 and 10 are equal.
    So we will get three possible isomers

  • Question 5
    1 / -0

    Which of the following connot be written in an isomeric form?

    Solution

    CH3​−CH(OH)−CH2​−CH3​ can have position isomer.
    CH3​−CHO can have functional isomers (enol).
    Cl−CH2​CH2​−Cl can have position isomer.
    But CH2​=CH−Cl has one isomer but it is not preferred IUPAC name.

  • Question 6
    1 / -0

    The number of cis-trans isomer possible for the following compound

     

    Solution


    Since only this is a double bond with different groups attached so only it will show cis-trans isomerism

  • Question 7
    1 / -0

    The number of isomers of dibromoderivative of an alkene (molear mass 186 g mol–1) is

    Solution

  • Question 8
    1 / -0

    Increasing order of stability among the three main conformation (i.e. eclipse, anti, gauche) of ethylene glycol is:

    Solution

    In the anti conformation the atoms are far apart ergo causing minimum repulsion whereas the opposite is true for eclipsed conformation. Gauche is in an in between stage.

  • Question 9
    1 / -0

    How many primary amines are possible for the formula C4H11N?

    Solution

    The following 4 structures are possible

  • Question 10
    1 / -0

    The R/S configuration of these compounds are respectively.

     

    Solution


    Applying the previously stated results we get A as the answer
     

  • Question 11
    1 / -0

    How many planes (pos) are presents in Anthracene

    Solution

  • Question 12
    1 / -0

    Two neighbours of homologous series differ by 

    Solution

    A homologous series is a series of compounds in which each member differs from the next/previous by CH2 or 14 mass units. Physical properties change in a homologous series but chemical properties remain almost the same because the functional group does not change.

  • Question 13
    1 / -0

    Geometrical isomers can be

    Solution

    Diastereomers are isomers which are not mirror images of each other, while enantiomers are those which are mirror images of each other. A geometric isomer without any chiral centre is a mirror image of itself. Also, 2 geometric isomers, which are not mirror images of each other will be diastereomers.
    Hence, geometrical isomers can be diastereomers or enantiomers.
     

  • Question 14
    1 / -0

    Phenol and benzyl alcohol are

    Solution

    Phenol is C6​H5​(OH) while benzyl alcohol is C6​H5​(CH2​OH). 
    Here there is a difference of −HC2​ between their molecular formula.
    According to the definition of homologous series, the adjacent members of the series differ by −CH2​ group.
    Thus, Phenol and benzyl alcohol are homologous of each other.

  • Question 15
    1 / -0

    C3H8 belongs to the homologous series of 

    Solution

    C3H6 and C4H8 belongs to same homologous series as they both belongs to alkene series whose formula is CnH2n, here n = no. of carbon atoms.

  • Question 16
    1 / -0

    Which of the follownig compounds is (S)–4-chloro-1-methylcyclohexene ?

    Solution

    Because when you see the question there is 1-methylcyclohexene this means the first numbering goes to methyl group and 'ene' group that is double bond and then it goes to 4 chloro that means from up to down including double bond we have to take chlorine on 4th position and it is (s) that means it is above the surface.

  • Question 17
    1 / -0

    Which of the following compounds has two stereogenic centers (asymmetric carbons) ?

    Solution

    Asymmetric carbon is the carbon which has all the four attached groups different.And these carbons are also called chiral carbons.
    Hence option A has asymmetric or chiral carbon.
    Hence option A is correct.

  • Question 18
    1 / -0

    Which of the following structures represents a chiral compound ?

    Solution

    This compound is chiral because its molecule has two chiral carbon atoms (C−3 and C-4).
    ether molecules are chiral due to the presence of a plane of symmetry.

  • Question 19
    1 / -0

    Examine the compound on the right. How many stereoisomers having this constitution are possible ?

    Solution

    Correct Answer :- d

    Explanation : 3 chiral centres

    Number of Stereoisomers = 2n

    = 23

    = 8

  • Question 20
    1 / -0

    Which of the following heptanols are chiral 1-heptanol, 2-heptanol, 3-heptanol, 4-heptanol.

    Solution

    As you can see, the third carbon atom from the left has three different groups attached to it namely 1. hydroxyl groups attached to namely 1. hydroxyl,
    2. ethyl
    3. n-butyl,
    4. hydrogen
    Hence the mentioned carbon atom is a chiral centre. Now any molecule having one chiral centre is a chiral molecule, i.e. 2 forms namely (R) and (S) forms of the molecule exist.
    Please note that if the molecule has more than one chiral centre, We cannot directly conclude that the molecule will be chiral.
     

  • Question 21
    1 / -0

    Which of the following will exhibit geometrical isomerism ?

    Solution

    1-phenyl-2-butene shows geometrical isomerism in the form of cis and trans isomers.
    However, the geometrical isomerism is not possible for 3-phenyl-1-butene, 2-phenyl-1-butene and 1,1-diphenyl-1-propane.

  • Question 22
    1 / -0

    Relation between given pair is

    Solution

    The above pairs are known as identical pair. An isomer of a molecule has the number of atoms of each element but has a  different arrangement of the atoms.It has  the same molecular  formula as the other molecule , with a different chemical structure.

  • Question 23
    1 / -0

    Following eclipsed form of propane is repeated after rotation of

  • Question 24
    1 / -0

    Stereoisomers differ from each other in what respect ?

    Solution

    Stereoisomers. Generally defined, stereoisomers are isomers that have the same composition (that is, the same parts) but that differ in the orientation of those parts in space.

  • Question 25
    1 / -0

    The number of isomers of C5H10 is

    Solution

    Correct Answer :- d

    Explanation : Given molecular formula is C5H10.

    ⇒ There are 6 isomeric alkenes by including Cis/trans isomers of pent−2−ene.

    ⇒ 7 Cycloalkanes also possible.

    Totally it have 13 isomers.

  • Question 26
    1 / -0

    The compound with the above configuration is called.

    Solution

    4th priority group always lie in vertical
    Clockwise: R
    Anticlockwise: S
    At 2nd carbon 1 → 2 → 3 configuration is r but 4 groups are horizontal so conf. change from R to s
    At 3rd carbon a → b → c conf. is r but d group is horizontal so conf. change from R to S
    Hence,
    2s,3s)-c-chloro-3 hydropentane

  • Question 27
    1 / -0

    The above compounds differ in

    Solution

    The first compound is in cis phase and the other one is trans phase. they differ in their structure.

  • Question 28
    1 / -0

    The compound C2H5OC2H5 and CH3OCH2CH2CH3 are

    Solution

    The compounds C2​H5​OC2​H5​ and CH3​OCH2​CH2​CH3​ are metamers.
    They differ in the nature of the alkyl groups.
     

  • Question 29
    1 / -0

    Which conformer of cyclohexane is chiral

    Solution

    We know that if a compound is symmetrical then then it is not chiral. hence chair conformation and boat conformations. Both are achiral whereas twist boat is chiral.

  • Question 30
    1 / -0

    Minimum C atoms required for a compound to show geometrical isomerism :

    Solution

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