Simple Harmonic...

A horizontal plank has a rectangular block placed on it. The plank starts oscillating vertically and simple harmonically with an amplitude of 40 cm. The block just loses contact with the plank when the later is momentarily at rest. Then

A body has a time period T₁ under the action of one force and T₂ under the action of another force, the square of the time period when both the forces are acting simultaneously in the same direction is

Motion of an oscillating liquid column in a U-tube is:

This time period of a particle undergoing SHM is 16s. It starts motion from the mean position. After 2s, velocity is 0.4 ms⁻¹. The amplitude is:

A particle is performing simple harmonic motion along the x-axis with amplitude 4 cm and time period 1.2 s. The minimum time taken by the particle to move from x = + 2 cm to x = + 4 cm and back again is given by:

The acceleration of a particle performing SHM is 12 cm sec⁻² at a distance of 3 cm from the mean position. Its time period is:

The acceleration d²x/dt² of a particle varies with displacement x as d²x/dt² = −kx

where k is a constant of the motion. The time period T of the motion is equal to :

A coin is placed on a horizontal platform, which undergoes horizontal SHM about a mean position O. The coin placed on the platform does not slip, the coefficient of friction between the coin and the platform is μ. The amplitude of oscillation is gradually increased. The coil will begin to slip on the platform for the first time:

A particle moves according to the law, x = r cos πt/2 . The distance covered by it in the time interval between t=0 to t=3 s is:

A particle is executing SHM of period 24 sec and of amplitude 41 cm with O as equilibrium position. The minimum time in seconds taken by the particle to go from P to Q, where OP=-9cm  and OQ=40cm is: